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almond37 [142]
3 years ago
6

Efficiency is given by A. actual output divided by effective capacity. B. design capacity divided by utilization. C. effective c

apacity divided by actual output. D. actual output divided by design capacity.
Physics
2 answers:
QveST [7]3 years ago
8 0

Answer:actual output divided by effective capacity.

Explanation:

Operational efficiency refers to the capability of any enterprise to deliver products or services to its customers in the most cost-effective manner possible while continually ensuring high quality of products, services and support. It is given by actual output divided by effective capacity multiplied by 100%.'

jok3333 [9.3K]3 years ago
5 0

Answer:

A

Explanation:

Actual output divided by the effective capacity. It is the ratio of output to effectiveness

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A steel wire of length 31.0 m and a copper wire of length 17.0 m, both with 1.00-mm diameters, are connected end to end and stre
Brut [27]

Answer:

The time taken is  t =  0.356 \ s

Explanation:

From the question we are told that

  The length of steel the wire is  l_1  = 31.0 \ m

   The  length of the  copper wire is  l_2  = 17.0 \ m

    The  diameter of the wire is  d =  1.00 \ m  =  1.0 *10^{-3} \ m

     The  tension is  T  =  122 \ N

     

The time taken by the transverse wave to travel the length of the two wire is mathematically represented as

              t  =  t_s  +  t_c

Where  t_s is the time taken to transverse the steel wire which is mathematically represented as

         t_s  = l_1 *  [ \sqrt{ \frac{\rho * \pi *  d^2 }{ 4 *  T} } ]

here  \rho_s is the density of steel with a value  \rho_s  =  8920 \ kg/m^3

   So

      t_s  = 31 *  [ \sqrt{ \frac{8920 * 3.142*  (1*10^{-3})^2 }{ 4 *  122} } ]

      t_s  = 0.235 \ s

 And

        t_c is the time taken to transverse the copper wire which is mathematically represented as

      t_c  = l_2 *  [ \sqrt{ \frac{\rho_c * \pi *  d^2 }{ 4 *  T} } ]

here  \rho_c is the density of steel with a value  \rho_s  =  7860 \ kg/m^3

 So

      t_c  = 17 *  [ \sqrt{ \frac{7860 * 3.142*  (1*10^{-3})^2 }{ 4 *  122} } ]

      t_c  =0.121

So  

   t  = t_c  + t_s

    t =  0.121 + 0.235

    t =  0.356 \ s

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Select the correct answer. Eli and Andy want to find out which of the two is stronger. Eli pushes a table with a force of 120 ne
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Acceleration of the table: B. 0.50 meters/second2

Explanation:

The problem can be solved by using Newton's second law of motion, which states that the net force acting on an object is the product of its mass and its acceleration. Mathematically:

\sum F = ma

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\sum F is the net force

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For the table in this problem, we have:

\sum F = 125 N - 120 N = 5 N is the net force on the table, because there are two forces of 125 N and 120 N acting in opposite  directions

m = 10.0 kg is the mass of the table

Solving for a, we find the acceleration:

a=\frac{\sum F}{m}=\frac{5}{10.0}=0.50 m/s^2

Learn more about Newton's second law:

brainly.com/question/3820012

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