<u>The question does not ask for anything in particular. I will calculate the acceleration and distance.</u>
Answer:
<em>The acceleration of the car is</em> 
<em>The distance traveled before stopping is 350 m</em>
Explanation:
<u>Constant Acceleration Motion</u>
It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.
Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:
![v_f=v_o+at\qquad [1]](https://tex.z-dn.net/?f=v_f%3Dv_o%2Bat%5Cqquad%20%5B1%5D)
The distance traveled by the object is given by:
![\displaystyle x=v_o.t+\frac{a.t^2}{2}\qquad [2]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3Dv_o.t%2B%5Cfrac%7Ba.t%5E2%7D%7B2%7D%5Cqquad%20%5B2%5D)
The car has an initial speed of v0=70 m/s when the driver sees a cow in the road and steps on the brakes with an (assumed) constant acceleration during t=10 seconds before stopping (vf=0).
With the information provided, we can calculate the value of the acceleration and the distance traveled.
Using the equation [1] we can solve for a:

Substituting the numerical values:

The acceleration of the car is 
The distance is now calculated by using [2]


The distance traveled before stopping is 350 m