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Zielflug [23.3K]
3 years ago
5

Strong solar winds blew dust and gas out of the solar system during which phase of the development of the Sun?

Physics
2 answers:
ipn [44]3 years ago
8 0
The choices can be found elsewhere and as follows:

a. <span>Alpha Centauri </span>
<span>c. </span><span>T-tauri </span>
<span>b. </span><span>The Big Bang </span>
<span>d. </span><span>Nebular
</span>
I believe the correct answer from the choices listed above is option D. <span>Strong solar winds blew dust and gas out of the solar system during Nebular phase. This seems to be the most logical option from the choices. Hope this helps. Have a nice day.</span>
sergejj [24]3 years ago
6 0

its T-tauri on Edge nuity

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The heat flux that is applied to one face of a plane wall is q″ = 20 W/m2. The opposite face is exposed to air at temperature 30
Blababa [14]

Answer:

400 W/m^2 and 31℃

Explanation:

The output heat flux q"= 20 W/m^2 (geven)

The output heat flux from.the wall to the air by convection

q"conv = h(ts - t∞)

q"conv = 20(50-30) = 400 W/m^2

Therefor, this case is unsteady and the wall temperature changes with time till the energy balance exist.

ENERGY BALANCE

The input energy must be equal to the output energy for steady state condition. If not the state will be unstaidy or transient.

2. Its noticed that the output heat flux is not that the I put heat flux, therefore the wall tempers will be decreased till the output heat flux is reduced to the value of the given input heat flux

T steady = T∞ +q"/h

= 30 + 20/20 = 31℃

3 0
3 years ago
Hydrogen is the second most abundant gas in the atmosphere? True or false?
Alenkinab [10]
False as oxygen is the second most abundant and nitrogen is the most abundant at 78%.
7 0
3 years ago
How much work does the electric field do in moving a proton from a point with a potential of +125 v to a point where it is -55 v
777dan777 [17]
The work W done by the electric field in moving the proton is equal to the difference in electric potential energy of the proton between its initial location and its final location, therefore:
W= qV_i - qV_f
where q is the charge of the proton, q=1 e = 1.6\cdot 10^{-19}C, with e being the elementary charge, and V_i = +125 V and V_f = -55 V are the initial and final voltage.

Substituting, we get (in electronvolts):
W=e(125 V-(-55 V))=180 eV
and in Joule:
W=(1.6 \cdot 10^{-19})(125 V-(-55V))=2.88 \cdot 10^{-17}J

5 0
3 years ago
Manuel is holding a 5 kg box. How much force us the box exerting on him? in what direction
Free_Kalibri [48]
It will be 49 Newtons of force in the down direction. To find the force in newtons, you multiply the mass (5 kg) by the gravity (which if 9.8). 
3 0
3 years ago
50 POINTS !!!
shepuryov [24]

Answer:

a) I = 464 kg m²,  b)  K = 631 .6 J, c)  v = 8.25 m / s

Explanation:

a) the moment of inertia of point particles is

          I = ∑ m_i r_i²

in this case

          I = 8 5² + 3 (-2) ² + 7 (-6) ²

          I = 464 kg m²

b) The kinetic energy is

          K = ½ I w²

          K = ½ 464 1.65²

          K = 631 .6 J

c) linear and angular velocity are related

          v = w r

          v = 1.65 5

          v = 8.25 m / s

8 0
2 years ago
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