Answer:
3.24m/s^2
Explanation:
The following data were obtained from the question:
U = 4m/s
V = 16m/s
t = 3.7secs
Acceleration is change in velocity with time i.e
a = (V — U) / t
a = (16 — 4) / 3.7
a = 12/3.7
a = 3.24m/s^2
Answer:
45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.
Explanation:
Using Ideal gas equation for same mole of gas as
Given ,
V₁ = 25.0 L
V₂ = ?
P₁ = 2575 mm Hg
Also, P (atm) = P (mm Hg) / 760
P₁ = 2575 / 760 atm = 3.39 atm
P₂ = 1.35 atm
T₁ = 353 K
T₂ = 253 K
Using above equation as:
Solving for V₂ , we get:
<u>V₂ = 45.0 L</u>
45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.
Answer:
Júpiter and 60000 the are the awnsers
Answer: They digest excess or worn out organelles, food particles, and engulfed viruses or bacteria.
Explanation:
Answer:
The answer to your question is: letter D
Explanation:
Data
Isotope mass 1 = 54 amu
Isotope mass 2 = 56 amu
Atomic weight = 54.37 amu
Percent abundance of isotope 2 = ? = X
Percent abundance of isotope 1 = 1 - x
Formula
Atomic weight = (Mass isotope 1)(1 - x) + (mass isotope 2)(x)
Process
Place the data in the formula and solve for x.
54.37 = 54( 1 - x) + 56x
54.37 = 54 - 54x + 56x
54.37 - 54 = -54x + 56x
0.37 = 2x
x = 0.37 / 2
x = 0.185
To find the percent multiply by 100
x = 0.185 x 100
x = 18.5 % = Mass of isotope 2
Mass of isotope 1 = 100 - 18.5 = 81.5 %
