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QveST [7]
2 years ago
12

How can speed be described?

Chemistry
2 answers:
Oxana [17]2 years ago
8 0

Answer:

The mass multiplied by the acceleration of an object.

Explanation:

Please give brainliest, It's not much, but it's honest work.

Svetach [21]2 years ago
7 0
The distance an object travels at a certain velocity
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Calculate the number of moles<br> 41.0 g of Ca(NO3)2 <br> 1.48 g of Ca(OH)2 <br> 3.40 g of CaSO4
Lemur [1.5K]
First. moles is just a label for a number of things. just like a dozen = 12, a gross = 144, a mole = 6022 with another 20 zeros after the 2

next

moles = mass / molecular weight.

molecular weight = sum of atomic mass from the periodic table

atomic mass MnO2 = atomic mass Mn + 2 x atomic mass O
= 54.94 + 2 x 16 = 86.94 g/mole

so moles MnO2 = 98.0 grams / (86.94 g/mole) = 1.13 moles

notice that I only gave 3 digits? that because of sig figs read the link below if you don't understand....

mw C5H12 = 5 x 12 + 12 x 1 = 72 g/mole

so moles C5H12 = 12.0 g / 72.0 g/mole = 0.167 moles

mw XeF6 = 131.3+ 6 x 19.00 = 245.3

so moles XeF6 = 100 g / 245.3 g/mole = 0.4077 moles

I've also provided a link to a periodic table. if you need atomic weights click on any element and it will give you the
details.
8 0
3 years ago
Giving brainiest to whoever answers correctly.
Digiron [165]

Answer:250

Explanation:

5 0
3 years ago
At 1000 K, Kp=19.9 for the reaction Fe2O3(s)+3CO(g)&lt;---&gt;2Fe(s)+3CO2(g) What are the equilibrium partial pressures of CO an
SOVA2 [1]

<u>Answer:</u> The equilibrium concentration of CO is 0.243 atm

<u>Explanation:</u>

We are given:

Initial partial pressure of carbon dioxide = 0.902 atm

As, carbon dioxide is present initially. This means that the reaction is proceeding backwards.

For the given chemical equation:

                      Fe_2O_3(s)+3CO(g)\rightleftharpoons 2Fe(s)+3CO_2(g)

<u>Initial:</u>                                                                  0.902

<u>At eqllm:</u>                            3x                           (0.902-3x)

The expression of K_p for above equation follows:

K_p=\frac{(p_{CO_2})^3}{(p_{CO})^3}

We are given:

K_p=19.9

Putting values in above equation, we get:

19.9=\frac{(0.902-3x)^3}{(3x)^3}\\\\x=0.0810

So, equilibrium concentration of CO = 3x = (3 × 0.0810) = 0.243atm[/tex]

Hence, the equilibrium concentration of CO is 0.243 atm

6 0
3 years ago
Read 2 more answers
A force of 12.5 N is appiled to 10 kg mass
lina2011 [118]
To find the acceleration, use the formula: force= mass x acceleration. 12.5 N = 10 x Acceleration Acceleration = 12.5 / 10 Acceleration = 1.25 Hope this helps :)
6 0
3 years ago
Question
Black_prince [1.1K]

Answer:

efef2w

Explanation:

7 0
2 years ago
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