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3 years ago

What periodic element is from Europe

Chemistry

2 answers:

Natasha2012 [34]3 years ago

8 0

I think it would be Europium

masya89 [10]3 years ago

3 0

Answer:

Europium

Explanation:

Europium

Europium was isolated in 1901 and is named after the continent of Europe.

Europium - Wikipediaen.wikipedia.org › wiki › Europium

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3 years ago

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How many grams of KC2H3O2 are needed to prepare 0.50L of a 6.00 M solution

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3 years ago

If 1.0 M HIM HI is placed into a closed container and the reaction is allowed to reach equilibrium at 25∘C∘C, what is the equili

sattari [20]

The given question is incomplete. The complete question is

If 1.0 M HI is placed into a closed container and the reaction is allowed to reach equilibrium at 25∘C∘C, what is the equilibrium concentration of H2 (g). Given the equilibrium constant is 62.

Answer: The equilibrium concentration of $H_2$ is 0.498 M

Explanation:

Initial concentration of $HI$ = 1.0 M

The given balanced equilibrium reaction is,

$2HI(g)\rightarrow H_2(g)+I_2(g)$

initial (1.0) M 0 0

At eqm (1.0-2x) M (x) M (x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[H_2]\times [I_2]}{[HI]^2}$

Now put all the given values in this expression, we get :

$62=\frac{(x)^2}{1.0-2x}$

By solving we get :

$x=0.498M$

Thus the equilibrium concentration of $H_2$ is 0.498 M

6 0

3 years ago

A 200.0 mL solution of 0.40 M ammonium chloride was titrated with 0.80 M sodium hydroxide. What was the pH of the solution after

Rus_ich [418]

Answer:

pH = 9.25

Explanation:

Step 1: Data given

Volume of a 0.40 M NH4Cl solution = 200.0 mL = 0.200 L

Molarity of NaOH = 0.80 M

Volume of NaOH = 50.0 mL

The Kb of ammonia is 1.76×10^-5

Step 2: The balanced equation

NH4Cl + NaOH → NH3 + NaCl + H2O

Step 3: Calculate moles

Moles NH4Cl = molarity *¨volume

Moles NH4Cl = 0.40 M * 0.200 L = 0.08 moles

Moles NaOH = 0.80 M * 0.050 L = 0.04 moles

Step 4: Calculate limiting reactant

NaOH will completely be consumed. (0.04 moles). NH44Cl is in excess. There will react 0.04 moles .there will remain 0.04 moles.

Step 5: Calculate moles NH3

Moles NH3 = for 0.4 moles NH4Cl we'll have 0.4 moles NH3

Step 6: Calculate molarity

Molarity = moles / volume

Molarity = 0.4 moles = 0.250 L

Molarity = 1.6 M

Step 7: Calculate pOH

pOH = pKb + log ([B+]/[BOH])

pOH = 4.75 + log (1.6 / 1.6)

pOH = 4.75

Step 8: Calculate pH

pH = 14 - 4.75

pH = 9.25

3 0

3 years ago