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Ksenya-84 [330]
2 years ago
8

Which of the substances evaporated first? and Which of the substances evaporated least?

Chemistry
1 answer:
Nuetrik [128]2 years ago
8 0

Answer:

The strength of the intermolecular forces in isopropyl alcohol are in between water and acetone, but probably closer to acetone because the water took much longer to evaporate. ... Acetone does not participate in hydrogen bonding, so its intermolecular forces are comparatively weaker, and it evaporates most quickly.

Explanation:

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Menthol is a flavoring agent extracted from peppermint oil. it contains c, h, and o. in one combustion analysis, 10.00 mg of the
marishachu [46]
Combustion reaction for menthol is as follows;
CxHyOz + O₂ ---> xCO₂ +  H₂O
Mass of CO₂ formed - 28.16 mg
Therefore number of moles formed - 28.16/ 44 g/mol = 0.64 mmol
Mass of water formed  - 11.53 mg
number of water moles formed - 11.53 mg/18 g/mol = 0.64 mmol
From CO₂,
1 mol of CO₂ - 1 mol of C and 2 mol of O
therefore number of C moles - 0.64 mmol
                                 O moles - 1.28 mmol
from H₂O
1 mol of H₂O - 2 mol of H and 1 mol of O
number of H moles - 1.28 mmol
                 O moles - 0.64 mmol

Mass of menthol initially - 10 mg
in reactions, the masses of products are equal to the masses of reactants. The excess mass to the products formed is due to O₂ in air
Original mass of menthol - 10 mg
mass of water and CO₂ - 11.53 mg + 28.16 mg = 39.69
Difference in mass - 39.69 - 10 = 29.69 mg
This difference comes from O moles in air - 29.69 mg/ 16 g/mol = 1.8556 mmol
then O moles coming from menthol - (1.28 + 0.64) - 1.8556 = 0.064 mmol

In menthol 
C moles - 0.64 mmol
H moles - 1.28 mmol
O moles - 0.064 mmol
ratios of C:H:O
C          H         O
0.64    1.28      0.064
x1000  x1000    x1000 to get whole numbers
640       1280      64
10          20          1
Simplest ratio of C:H:O is 10:20:1
therefore empirical formula of menthol is C₁₀H₂₀O


5 0
3 years ago
90 grams of NaNO3 were added to solution at 10 degrees Celsius. What type of solution was formed?
vichka [17]

Answer:

friend me on here and imma send you the link Explanation:

4 0
3 years ago
19. This type of bond involves the bonding of two ions of opposite charges
hammer [34]

Answer:

Covalent bond is a type of bond involves the bonding of two ions of opposite charges.

<h3><u>PLEASE</u><u> MARK</u><u> ME</u><u> BRAINLIEST</u><u>.</u></h3>
7 0
2 years ago
3. The following data of decomposition reaction of thionyl chloride (SO2Cl2) were collected at a certain temperature and the con
KonstantinChe [14]

Answer:

a) First-order.

b) 0.013 min⁻¹

c) 53.3 min.

d) 0.0142M

Explanation:

Hello,

In this case, on the attached document, we can notice the corresponding plot for each possible order of reaction. Thus, we should remember that in zeroth-order we plot the concentration of the reactant (SO2Cl2 ) versus the time, in first-order the natural logarithm of the concentration of the reactant (SO2Cl2 ) versus the time and in second-order reactions the inverse of the concentration of the reactant (SO2Cl2 ) versus the time.

a) In such a way, we realize the best fit is exhibited by the first-order model which shows a straight line (R=1) which has a slope of -0.0013 and an intercept of -2.3025 (natural logarithm of 0.1 which corresponds to the initial concentration). Therefore, the reaction has a first-order kinetics.

b) Since the slope is -0.0013 (take two random values), the rate constant is 0.013 min⁻¹:

m=\frac{ln(0.0768)-ln(0.0876)}{200min-100min} =-0.0013min^{-1}

c) Half life for first-order kinetics is computed by:

t_{1/2}=\frac{ln(2)}{k}=\frac{ln(2)}{0.013min^{-1}}  =53.3min

d) Here, we compute the concentration via the integrated rate law once 1500 minutes have passed:

C=C_0exp(-kt)=0.1Mexp(-0.013min^{-1}*1500min)\\\\C=0.0142M

Best regards.

6 0
3 years ago
Transamination of an amino acid transfers an amine group to form an α‑keto acid and is catalyzed by transaminases. Some amino ac
iragen [17]

Answer:

Amino acids that fall under the first category are alanine, aspartate and glutamate. While amino acids that fall under the second category are glycine, valine, proline, leucine, isoleucine, methionine, serine, threonine, cysteine, asparagine, glutamine, phenylalanine, tryptophan, tyrosine, lysine, arginine and histidine

Explanation:

Alanine, a 3-carbon amino acid reacts with α-ketoglutarate, a 5-carbon ketoacid, to produce pyruvate, a 3-carbon compound which is one of the glycolytic products in aerobic respiration, and glutamate, a 5-carbon amino acid, with the aid of alanine transaminase (ALT). The amino group from alanine is transfered from the α-carbon of alanine to the α-carbon of the α-ketoglutarate.

Aspartate, a 4-carbon amino acid also reacts with α-ketoglutarate to form oxaloacetate, a 4-carbon ketoacid which is present as an intermediate in the citric acid cycle, and glutamate. The amino group transfer occurs between the α-carbon of aspartate and the α-carbon of α-ketoglutarate.

Unlike the presence of a ketoacid in the conversion of alanine and aspartate to their corresponding amino acids, glutamate conversion to α-ketoglutarate, an intermediate in the citric acid cycle, involves no ketoacids as an amino group acceptor from glutamate. The amino group is freely released as an ammonium ion. The reaction involves the presence of a cofactor, NAD+ or NADP+, water (H2O) and glutamate dehygrogenase (GDH).

Other amino acids involve several metabolic steps to be converted into glycolytic or citric acid intermediates.

7 0
3 years ago
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