Which is more volatile benzene or toluene?

What is the main reason that the bounce height decrease.

tiny-mole [99]

Since there is loss of kinetic energy

5 0

3 years ago

As temperature increases, density increases. True or False

Alex73 [517]

Density increases with the temperature, true.

4 0

3 years ago

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An analytical chemist weighs out 0.093g of an unknown monoprotic acid into a 250mL volumetric flask and dilutes to the mark with

Kamila [148]

Answer:

The molar mass of the unknown acid is 89 g/mol

Explanation:

Step 1: The balanced equation

HA(aq) + NaOH(aq) → NaA(aq) + H2O(l)

It takes 1 mole of NaOH to neutralize 1 mole of the triprotic acid. This is called the reaction stoichiometry.

Step 2: Data given

Mass of the acid = 0.093 grams

volume = 250 mL

titrates with 0.16 M NaOH

adds 6.5 mL NaOH

Step 3: Calculate moles of NaOH

We know the concentration and volume of NaOH needed to neutralize the acid.

By determining the moles of NaOH in that volume in liters (95.9mL=0.0959L), the moles of acid in the original sample can be determined from the reaction stoichiometry.

Moles = Molarity * Volume

Moles = 0.16 M * 0.0065 L

Moles = 0.00104 moles NaOH

Step 4: Calculate moles of the unknown acid:

It takes 1 mole of NaOH to neutralize 1 mole of the triprotic acid. This is called the reaction stoichiometry.

For 0.00104 moles NaOH we have 0.00104 moles of HA

Step 5: Calculate the molar mass of the acid

Molar mass Ha = Mass Ha / moles Ha

Molar mass Ha = 0.093 grams / 0.00104 moles

Molar mass Ha = 89.42 g/mol ≈89 g/mol

The molar mass of the unknown acid is 89 g/mol

3 0

3 years ago

The Lewis dot model of a molecule is shown. A visual diagram of a PCl3 molecule is shown. Phosphorous is the central atom with a

Nostrana [21]

The answer is B. Each chlorine has three non-bonded pairs and one bonded pair of electrons.

I just took the test and it was correct! 5/5 :)

8 0

3 years ago

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Elemental iodine (I 2) is a solid at room temperature. What is the major attractive force that exists among different I 2 molecu

Ulleksa [173]

Explanation:

As $I_{2}$ is a covalent compound because it is made up by the combination of two non-metal atoms. Atomic number of an iodine atom is 53 and it contains 7 valence electrons as it belongs to group 17 of the periodic table.

Therefore, sharing of electrons will take place when two iodine atoms chemically combine with each other leading to the formation of a covalent bonding.

Hence, weak forces like london dispersion forces will be present between a molecule of $I_{2}$ .

The weak intermolecular forces which can arise either between nucleus and electrons or between electron-electron are known as dispersion forces. These forces are also known as London dispersion forces and these are temporary in nature.

thus, we can conclude that london dispersion force is the major attractive force that exists among different $I_{2}$ molecules in the solid.

7 0

3 years ago