What is the mass number of an atom with 3 protons and 4 neutrons and 3 electrons
1 answer:
You might be interested in
The heat absorbed by the water sample for vaporization has been 6,105 kJ. Thus, option D is correct.
The heat of vaporization has been the amount of heat required to vaporize 1 gram of liquid.
The heat required for the vaporization has been given as:
The heat of vaporization of water has been given as,
The mass of water sample has been,
Substituting the values for the heat energy absorbed, <em>Q:</em>
<em />
<em />
The heat absorbed by the water sample for vaporization has been 6,105 kJ. Thus, option D is correct.
Learn more about heat of vaporization, here:
Explanation:
(a). The given data is as follows.
Volume of one glass of water = ml = 220 ml
Volume of 4 glass of water = = 880 ml
We known that density of water is 1 g/ml. Therefore, calculate the mass of water as follows.
Mass of water =
= 880 gm
= 0.88 Kg (as 1 kg = 1000 g)
The relation between heat energy, mass and temperature change is as follows.
Q =
Putting the given values into the above formula as follows.
Q =
=
= 124.5 kJ
Hence, the body have to supply 124.5 kJ to raise the temperature of the water to 37 degree C.
(b). As we know that the heat of fusion of ice is 333 J/g.
So, energy required for g or 840 g is as follows.
= 279.72 kJ
Heat capacity of water= 4.184
Now, heat energy will be as follows.
Q =
= 130.03 kJ
Therefore, total heat required = (279.72 + 130.03) kJ
= 409.75 kJ
Hence, for the given situation your body should lose 409.75 kJ of heat.