What is the mass number of an atom with 3 protons and 4 neutrons and 3 electrons

Calculate the standard cell potential given the following standard reduction potentials: Al3++3e−→Al;E∘=−1.66 V Cu2++2e−→Cu;E∘=0

Maru [420]

Answer:

Explanation:

To calculate the cell potential we use the relation:

Eº cell = Eº oxidation + Eº reduction

Now in order to determine which of the species is going to be oxidized, we have to remember that the more the value of the reduction potential is negative, the greater its tendency to be oxidized is. In electrochemistry we use the values of the reductions potential in the tables for simplicity because the only thing we need to do is change the sign of the reduction potential for the oxized species .

So the species that is going to be oxidized is the Aluminium, and therefore:

Eº cell = -( -1.66 V ) + 0.340 V = 5.06 V

Equally valid is to write the equation as:

Eº cell = Eº reduction for the reduced species - Eº reduction for the oxidized species

These two expressions are equivalent, choose the one you fell more comfortable but be careful with the signs.

3 0

3 years ago

HNO3 + S --> H2SO4 + NO Now identify the element oxidized and the element reduced. Which element is oxidized? Which element i

OleMash [197]

Answer: S is getting oxidized, N is getting reduced and O and H undergo no oxidation or reduction

Explanation:

The oxidation reaction is defined as the reaction in which a chemical species loses electrons in a chemical reaction. It occurs when oxidation number of a species increases.

A reduction reaction is defined as the reaction in which a chemical species gains electrons in a chemical reaction. It occurs when oxidation number of a species decreases.

For the given chemical reaction:

$HNO_3+S\rightarrow H_2SO_4+NO$

On the reactant side:

Oxidation number of H = +1

Oxidation number of N = +5

Oxidation number of O = -2

Oxidation number of S = 0

On the product side:

Oxidation number of H = +1

Oxidation number of N = +2

Oxidation number of O = -2

Oxidation number of S = +6

As the oxidation number of S is increasing from 0 to +6. Thus, it is getting oxidized. Similarly, the oxidation number of N is decreasing from +5 to +2. Thus, it is getting reduced.

The oxidation numbers of O and H remain the same on both sides of the reaction. Thus, they are neither getting oxidized or reduced.

Hence, S is getting oxidized, N is getting reduced and O and H undergo no oxidation or reduction

3 0

3 years ago

Why the bonds between nonmentals tend to be covalent

natita [175]

Ionic bonds form when a nonmetal and a metal exchange electrons, while covalent bonds form when electrons are shared between two nonmetals. An ionic bond is a type of chemical bond formed through an electrostatic attraction between two oppositely charged ions.

7 0

3 years ago

elements on the right side of the periodic table differ from the elements on the left side in that elements on the right side

yarga [219]

Element on the right side of the periodic table differ from the elements on the left side in that elements on the right side are non metallic and tends to be gases at room temperature.

Explanation

In the periodic table there element in the right side , left side and those which are in between.

Example of element in the right side is fluorine chlorine, neon, Argon among others.

This element have higher effective nuclear charges and stabilize electrons more effectively.
there electrostatic intermolecular forces are generally weak therefore they exist in liquid or gaseous state.

7 0

3 years ago

A 4.3 L gas bubble at STP is heated to 984 K, and the pressure increases to 1520 mmHg. What is the new volume?

Natalka [10]

Answer:

v2=40.35L

Explanation:

p1v1/t1=p2v2/t2

v2=t2p1v1/t1p2

v2=984*760*22.4/273.15*1520

v2=40.35 L

5 0

3 years ago