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dmitriy555 [2]
4 years ago
15

Choose the FALSE statement about a fly ball as it travels from a batter's bat to a center fielder who catches the ball.

Physics
2 answers:
Murrr4er [49]4 years ago
5 0

A, B, and C are true statements.

D is the false statement.

mr Goodwill [35]4 years ago
3 0

D. is the false answer!

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Some people say you can tell if someone has HIV by looking at him or her. True or false? Why?
Alex17521 [72]

Answer:False.

Explanation: HIV is a viruse that only shows symptoms after a few weeks. in Fact HIV does not show any physical symptoms. So, no you can not tell if someone has or is been infected by HIV by directly looking at them.

Have a Nice Day!!! =)

5 0
3 years ago
Read 2 more answers
Two identical ambulances with loud sirens are driving directly towards you at a speed of 40 mph. One ambulance is 2 blocks away
Rasek [7]

Answer:

c) The pitch of the two sirens sounds the same to you

Explanation:

The pitch does not depend on the distance of the object from the observer.

As per the given data

pitch = frequency

Frequency = f_{0}  \frac{V +- V_{0}}{V +- V_{s}}

f^{'} = f_{0}  \frac{V }{V - V_{s}}

Hence, the pitch of the two sirens remains the same for the observer.

5 0
3 years ago
Read 2 more answers
What is the terminal velocity of a 6.00-kg mass object in falling with a drag force with a magnitude that depends on speed, v, a
3241004551 [841]

When object reached the terminal speed then its acceleration is zero

So as per Newton's II law we can say

F_{net} = 0

now in that case we can say that net force is zero so here weight of the object is counter balanced by the drag force when it will reach at terminal speed

so we can write

mg - F_d = 0

so here we are given that

F_d = 30

6*9.8 - 30*v = 0

58.8 - 30 *v = 0

v = \frac{58.8}{30}

v = 1.96 m/s

so terminal speed will be nearly 2 m/s

6 0
3 years ago
A 0.015 kg marble sliding to the right at 22.5 cm/s on a frictionless surface makes an elastic head-on collision with a 0.015 kg
slava [35]

Answer:

Explanation:

mass of first marble m_1=m=0.015\ kg

Initial velocity of the first marble u_1=22.5\ m/s

considering right side as positive

Mass of second marble

m_2=m=0.015\ kg\\u_2=-18\ cm/s

After collision first marble moves to the left with a velocity of 18 cm/s

i.e. v_1=-18\ cm/s

considering v_2 be the velocity of second marble after collision

The Coefficient of restitution is 1 for an elastic collision

e=\frac{v_2-v_1}{u_1-u_2}

Putting values

1=\frac{v_2-(-18)}{22.5-(-18)}\\22.5+18=v_2+18\\v_2=22.5\ m/s

So, the velocity of the second marble is 22.5 m/s to the right after the collision

(b)Initial kinetic energy =0.5\times 0.015\times (22.5\times 10^{-2})^2+0.5\times 0.015\times (18\times 10^{-2})^2=6.22\times 10^{-4}\ J

Final kinetic energy=

0.5\times 0.015\times (18\times 10^{-2})^2+0.5\times 0.015\times (22.5\times 10^{-2})^2=6.22\times 10^{-4}\ J

6 0
3 years ago
A 290 gg bird flying along at 6.2 m/sm/s sees a 9.0 gg insect heading straight toward it with a speed of 34 m/sm/s (as measured
Murrr4er [49]

Answer:

The bird's speed immediately after swallowing is 4.98 m/s.

Explanation:

Given that,

Mass of bird = 290 g

Speed = 6.2 m/s

Mass of sees = 9.0 g

Speed = 34 m/s

We need to calculate the bird's speed immediately after swallowing

Using conservation of momentum

m_{1}v_{1}+m_{2}v_{2}=(m_{1}+m_{2})v_{3}

Put the value into the formula

0.290\times6.2+0.009\times(-34)=(0.290+0.009)\times v_{3}

v_{3}=\dfrac{0.290\times6.2-0.009\times34}{(0.290+0.009)}

v_{3}=4.98\ m/s

Hence, The bird's speed immediately after swallowing is 4.98 m/s.

6 0
3 years ago
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