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MAVERICK [17]
2 years ago
6

How to find velocity of center of mass before and after the collision

Physics
1 answer:
statuscvo [17]2 years ago
8 0

Hey there! I'll try to provide you with my best answer.

Answer: In a collision, the velocity change is always computed by subtracting the initial velocity value from the final velocity value. If an object is moving in one direction before a collision and rebounds or somehow changes direction, then its velocity after the collision has the opposite direction as before.

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How do volcanoes above hot spots differ from volcanoes above subduction zones?
BARSIC [14]
C. Volcanoes above subduction zones have lava that is not basaltic.
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2 years ago
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1.
charle [14.2K]

Answer:

i love devon bostick

Explanation:

cause....... i do

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3 years ago
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A force of 825 N is needed to push a car across a parking lot. Two students push a car 35 m. How much total work is done?
MaRussiya [10]
<h2>Answer :</h2><h2 />

Work is the amount of energy transferred. As per the formula

Work = Force x Distance [moved toward the direction of the force]

So as per the formula

<u>Solution : </u>

Force = 825 N

Distance = 35 m

Work = 825 (n) x 35 (m)

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6 0
3 years ago
A satellite orbiting Earth at an orbital radius r has a velocity v. Which represents the velocity if the satellite is moved to a
satela [25.4K]

Answer:

The correct answer is V√5

Explanation:

Let V be the velocity of the satellite orbiting at radius r.

Let V(5r) be the velocity of the satellite orbiting at radius 5r.

Recall:

Escape velocity is given by:

V = √(2gr)

Where V is the escape velocity

g is the acceleration due to gravity

r is the radius of the earth.

With the above equation, we can obtain the answer to the question as follow:

V = √(2gr)

V(5r) = √(2g5r)

Next, we'll obtained the ratio of V(5r) to V as shown below

V(5r) : V => V(5r)/V

V(5r)/V = √(2g5r) / √(2gr)

V(5r)/V = √5

Cross multiply

V(5r) = V√5

From the above illustration, we can see that when the satellite is moved to 3r, then the expression for the velocity will be V√5

3 0
3 years ago
Striking a fixed object at 60 MPH is the same as falling from a _____ story building:
yulyashka [42]

speed of the striking object is given as

v = 60 mph

now this speed in SI units given as

v = 60 \times \frac{1609 m}{3600 s}

v = 26.82 m/s

So here we can use kinematic now to find the height from where it is dropped

so here we will have

v_f^2 - v_i^2 = 2 a d

now we have

v_f = 26.82 m/s

v_i = 0

a = 9.81 m/s^2

now from above equation

26.82^2 - 0 = 2(9.81)d

d = 36.67 m

now we know that average height of 1 story building is 3 meter

so approx total number of stories in the building will be

N = \frac{36.67}{3} = 12 story

6 0
3 years ago
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