C.
The force of friction = coefficient of friction * normal force.
Adding the book to the boy increases the normal force and the component of the gravitational force directed down the slide. This in turn increases the force of friction as can be seen by the relationship from the above equation. For a stationary object, the force of static friction is always equal to the force applied (in this case, it is the component of the gravitational force directed down the slide). That means that so long as the boy is not moving and his mass increases, the frictional force is increasing also to balance the increased downward gravitation force directed down the slide.
Try looking up facts about physics or referring back to your notes in class. :)
6025loveteal
Anything that's dropped on or near the Earth accelerates at the rate of
9.8 m/s² on its way down. The mass of the object makes no difference.
After falling for 2 seconds, it's falling at the rate of 19.6 m/s.
Momentum = (mass) x (speed)
The egg's momentum is (5.07 kg) x (19.6 m/s) = 99.4 kg-m/s .
Answer:
d = 0.076 mm
Explanation:
Given data
diffraction pattern d1 = 0.19 mm = 0.019 cm
separated s(1) = 1.8 cm
separated s(2) = 4.5 cm
to find out
d2 for an unknown
solution
we know here that spacing in between the diffraction fringe is always inversely proportional to diffraction grating so
we will apply here formula for unknown d that is
d1 (s1 / L) = d2 (s2 /L)
d2 = d1 × s(1) / s(2)
put here all thes evalue we get d2
d2 = d1 × s(1) / s(2)
d2 = 0.019 × 1.8 / 4.5
d2 = 0.0076 cm
d2 = 0.076 mm
