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sergejj [24]
3 years ago
8

The ____ in an arithmetic sequence can be found by subtracting the first term from the second term

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
7 0
The [common difference, d, ] in an arithmetic sequence can be found by subtracting the first term from the second term
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The sum of a number xx and 4 equals 12. an equation that represents this sentence is
lora16 [44]
X + 4 = 12

This is because the question gives you everything you require for this sentence to be formed. 12 is the final answer. 4 is added on and x is basically the number that is to be found.
5 0
2 years ago
Pls help ASAP pls pls pls i will give brainliest if 2 people reply whichever gives best explanation will get brainliset
riadik2000 [5.3K]

Answer:

3 1/3 miles The answer is D

Step-by-step explanation:

The first trip to school is 5/6 miles. Multiply that by 2 because she also walked home and you get 10/6. Then add the distance she she walked to the library- which simplifies to 5/6 and you get 20/6. That simplifies to 3 1/3.

3 0
2 years ago
Read 2 more answers
as a cure to the epidemic that spread in the whole country, the department of health released a new drug that is subject for exp
nlexa [21]

Answer:

Your smart maybe

Step-by-step explanation:

5 0
2 years ago
the half life of c14 is 5730 years. Suppose that wood found at an archeological excavation site contains about 35% as much C14 a
Furkat [3]

Answer:

The wood was cut approximately 8679 years ago.

Step-by-step explanation:

At first we assume that examination occured in 2020. The decay of radioactive isotopes are represented by the following ordinary differential equation:

\frac{dm}{dt} = -\frac{m}{\tau} (Eq. 1)

Where:

\frac{dm}{dt} - First derivative of mass in time, measured in miligrams per year.

\tau - Time constant, measured in years.

m - Mass of the radioactive isotope, measured in miligrams.

Now we obtain the solution of this differential equation:

\int {\frac{dm}{m} } = -\frac{1}{\tau}\int dt

\ln m = -\frac{1}{\tau} + C

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} } (Eq. 2)

Where:

m_{o} - Initial mass of isotope, measured in miligrams.

t - Time, measured in years.

And time is cleared within the equation:

t = -\tau \cdot \ln \left[\frac{m(t)}{m_{o}} \right]

Then, time constant can be found as a function of half-life:

\tau = \frac{t_{1/2}}{\ln 2} (Eq. 3)

If we know that t_{1/2} = 5730\,yr and \frac{m(t)}{m_{o}} = 0.35, then:

\tau = \frac{5730\,yr}{\ln 2}

\tau \approx 8266.643\,yr

t = -(8266.643\,yr)\cdot \ln 0.35

t \approx 8678.505\,yr

The wood was cut approximately 8679 years ago.

5 0
3 years ago
×
german

Let

x------> hours worked by Sara last week

y------> hours worked by Joan last week

z------> hours worked by Erin last week

we know that

x=28 hours ------> equation 1

y=x-6-----> equation 2

substitute the value of x in equation 2

y=28-6=22 hours

z=y/2------> equation 3

substitute the value of y in the equation 3

z=22/2=11 hours

<u>the answer is</u>

Sara worked 28 hours last week

Joan worked 22 hours last week

Erin worked 11 hours last week

4 0
3 years ago
Read 2 more answers
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