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3 years ago

What are the characteristics of the image based on the values?Check all that apply

Physics

2 answers:

Ahat [919]3 years ago

8 0

inverted, real, behind the lens is the answer

kifflom [539]3 years ago

7 0

Answer:

Inverted

Real

Behind the lens

Explanation:

As we know that

$d_o = 16 cm$

$d_i = 16 cm$

also we know that

$h_o = 4 cm$

$h_i = -4 cm$

now we know that magnification is given by

$M = \frac{d_i}{d_o} = \frac{h_i}{h_o}$

so we can say here that

M = 1

so here image size will be same as object size and it must be real and inverted as magnification is negative in sign

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How many earths could fit inside jupiter

Snezhnost [94]

1,300 or more.

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3 years ago

How much water can be held by a cylindrical tank with a radius of 12 feet and a height of 30 feet? A. 2,260.8 cubic feet B. 13,5

MakcuM [25]

Answer:

Volume, V = 13564.8 cubic feet

Explanation:

It is given that,

Radius of the cylindrical tank, r = 12 feet

Height of the tank, h = 30 feet

We need to find the water that can be held by a cylindrical tank i.e. we need to find the volume of the tank. It is given by :

$V=\pi\times r^2\times h$

$V=3.14\times (12)^2\times 30$

V = 13564.8 cubic feet

So, the water held by the tank is 13564.8 cubic feet. Hence, this is the required solution.

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2 years ago

A car is driven off a cliff at 39 m/s. It lands 141 m from the base. How high

Mumz [18]

Answer: A

Explanation: STEP BY STEP

4 0

2 years ago

A cylindrical capacitor has an inner conductor of radius 2.7 mmmm and an outer conductor of radius 3.1 mmmm. The two conductors

Mars2501 [29]

Answer:

(A) Capacitance per unit length = $4.02 \times 10^{-10}$

(B) The magnitude of charge on both conductor is $Q = 4.22 \times 10^{-19}$ C and the sign of charge on inner conductor is $+Q$ and the sign on outer conductor is $-Q$

Explanation:

Given :

Radius of inner part of conductor $(R_{1})$ = $2.7 \times 10^{-3}$ m

Radius of outer part of conductor $(R_{2})$ = $3.1 \times 10^{-3}$ m

The length of the capacitor $(l)$ = $3 \times 10^{-3}$ m

(A)

Capacitance is purely geometrical property. It depends only on length, radius of conductor.

From the formula of cylindrical capacitor,

$C = \frac{2\pi\epsilon_{o} l }{ln\frac{R_{2} }{R_{1} } }$

Where, $\epsilon_{o} = 8.85 \times 10^{-12}$

But we need capacitance per unit length so,

$\frac{C}{l} = \frac{2\pi\epsilon_{o} }{ln\frac{R_{2} }{R_{1} } }$

capacitance per unit length = $\frac{6.28 \times 8.85 \times 10^{-12} }{ln(1.148)} = 4.02 \times 10^{-10}$

(B)

The charge on both conductors is given by,

$Q = C \Delta V$

Where, C = capacitance of cylindrical capacitor and value of $C = 12.06 \times 10^{-13}$ F, $\Delta V = 350 \times 10^{-3}$ V

∴ $Q = 4.22 \times 10^{-19}$ C

The magnitude of charge on both conductor is same as above but the sign of charge is different.

Charge on inner conductor is $+Q$ and Charge on outer conductor is $-Q$ .

8 0

3 years ago

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3 years ago