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Anni [7]
3 years ago
10

What are the characteristics of the image based on the values?Check all that apply

Physics
2 answers:
Ahat [919]3 years ago
8 0

inverted, real, behind the lens is the answer

kifflom [539]3 years ago
7 0

Answer:

Inverted

Real

Behind the lens

Explanation:

As we know that

d_o = 16 cm

d_i = 16 cm

also we know that

h_o = 4 cm

h_i = -4 cm

now we know that magnification is given by

M = \frac{d_i}{d_o} = \frac{h_i}{h_o}

so we can say here that

M = 1

so here image size will be same as object size and it must be real and inverted as magnification is negative in sign

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It’s frequency is high and microwaves can pass through the atmosphere of the Earth.
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a motorcycle is capable of accelerating at 5.1 m/s starting from rest how far can it travell in 1.5 sec
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The answer is 21m because the motion is in one dimension with constant acceleration.

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Plugging in our known values, we have

<span>Δx=<span>(0)</span><span>(3.0s)</span>+<span>12</span><span>(4.7<span>m<span>s2</span></span>)</span><span><span>(3.0s)</span>2</span>=<span>21<span>m</span></span></span>

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What does convection mean
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3 years ago
One of the harmonic frequencies of tube A with two open ends is 576 Hz. The next-highest harmonic frequency is 648 Hz. (a) What
balu736 [363]

(a) 288 Hz

The difference between any two harmonics of an open-end tube is equal to the fundamental frequency, f_1 (first harmonic):

f_{n+1}-f_n = f_1 (1)

In this problem, we are told the frequencies of two successive harmonics:

f_n = 576 Hz\\f_{n+1}=648 Hz

So the fundamental frequency is:

f_1 = 648 Hz-576 Hz=72 Hz

Now we know that one of the the harmonics is f_n=216 Hz, so its next highest harmonic will have a frequency of

f_{n+1}=f_n+f_1 = 216 Hz+72 Hz=288 Hz

(b) n=4

The frequency of the nth-harmonic is an integer multiple of the fundamental frequency:

f_n=n f_1 (2)

Since we know f_n = 288 Hz, we can solve (2) to find the number n of this harmonic:

n=\frac{f_n}{f_1}=\frac{288 Hz}{72 Hz}=4

(c) 4445 Hz

For a closed pipe (only one end is open), the situation is a bit different, because only odd harmonics are allowed. This means that the frequency of the nth-harmonic is an odd-integer multiple of the fundamental frequency:

f_n=(2n+1) f_1 (2)

so, the difference between any two harmonics tube is equal to:

f_{n+1}-f_n = (2(n+1)+1)f_1-(2n+1)f_1=(2n+3)f_1-(2n+1)f_1=2f_1 (1)

In this problem, we are told the frequencies of two successive harmonics:

f_n = 4699 Hz\\f_{n+1}=4953 Hz

So, according to (1), the fundamental frequency is equal to half of this difference:

f_1 = \frac{4953 Hz-4699 Hz}{2}=127 Hz

Now we know that one of the harmonics is f_n=4191 Hz, so its next highest harmonic will have a frequency of

f_{n+1}=f_n+2f_1 = 4191 Hz+254 Hz=4445 Hz

(d) n=17

We said that the frequency of the nth-harmonic is equal to an odd-integer multiple of the fundamental frequency:

f_n=(2n+1) f_1 (2)

Since we know f_n = 4445 Hz, we can solve (2) to find the number n of this harmonic:

n=\frac{1}{2}(\frac{f_n}{f_1}-1)=\frac{1}{2}(\frac{4445 Hz}{127 Hz}-1)=17

7 0
3 years ago
A graph titled Position versus time for with horizontal axis time (seconds) and vertical axis position (meters). A straight blue
ankoles [38]

Answer:

starting position: 3 m

velocity: 3 m/s

Explanation:

at t=0 position= 3 m

velocity: (delta)position/(delta)time

(delta=change in)

velocity= (15-3)/(4-0)

velocity= 12/4

velocity= 3 m/s

6 0
2 years ago
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