Answer:
Part a)

Part b)
v = 3.64 m/s
Part c)

Part d)

Explanation:
As we know that moment of inertia of hollow sphere is given as

here we know that

R = 0.200 m
now we have


now we know that total Kinetic energy is given as





Part a)
Now initial rotational kinetic energy is given as



Part b)
speed of the sphere is given as
v = 3.64 m/s
Part c)
By energy conservation of the rolling sphere we can say




Part d)
Now we know that




The turns ratio is equal to the voltage ratio. Let n1 and n2 be the primary and secondary turns. Then
5850V/120V=n1/n2
48.75=2680/n2
n2=2680/48.75
n2=55
Given:
The mass of the halfback is m = 107 kg
The speed of the halfback is v = 8 m/s
To find the momentum.
Explanation:
The momentum of the halfback is

Thus, the momentum of the halfback is 856 kg m/s
Explanation:
Given that,
Mass of the object, m = 7.11 kg
Spring constant of the spring, k = 61.6 N/m
Speed of the observer, 
We need to find the time period of oscillation observed by the observed. The time period of oscillation is given by :

Time period of oscillation measured by the observer is :

So, the time period of oscillation measured by the observer is 5.79 seconds.