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myrzilka [38]
4 years ago
8

Birds, squirrels, and chipmunks all living in the same tree, using the same resources, are an example of:

Physics
1 answer:
Ulleksa [173]4 years ago
4 0

Explanation :  

In Interspecific competition, different individuals of different species fight for the same resource in an ecosystem. The resources can be food or living space.

Birds belong to the group of<em> aves</em>, squirrels and chipmunks are from the family of <em>Sciuridae</em>.  

All three are from different species. They are on the same ecosystem i.e. tree. They form the interspecific competitions.

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<span>a) All the 26m should be used to bent into a square to maximize the total area (= 42.25 m2) b) 1.4136m should be bent into a square and the rest (= 24.586m) should be bent into an equilateral triangle to minimize the total area (= 29.0835m2)</span>
8 0
3 years ago
Two identical blocks of iron are placed in contact, one at 10°C and the other at 20°C. If the cooler block cools to 5°C and the
Alenkinab [10]

Answer:

this is violation of II law of thermodynamics

Explanation:

As per 2nd law of thermodynamics we know that heat always flows from high temperature to low temperature

If heat flows from low temperature to high temperature then it is only possible when some external work is done on the system

So here it says that initially two blocks are at 10 degree C and 20 degree C

Now the cool object will become cooler and hot object becomes hotter

which shows that heat is flowing from low temperature to high temperature

So this is violation of II law of thermodynamics

8 0
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What are some ways scientists can study the seafloor?
TiliK225 [7]

Answer: A device records the time it takes sound waves to travel from the surface to the ocean floor and back again. Sound waves travel through water at a known speed. Once scientists know the travel time of the wave, they can calculate the distance to the ocean floor.

Explanation:

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3 years ago
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List these things in order of size, starting with the smallest thing:
jek_recluse [69]
Moon, earth, sun solar system, galaxy, universe
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The position of a particle moving along an x axis is given by x = 14.0t2 - 2.00t3, where x is in meters and t is in seconds. det
Mumz [18]

a) x = 14t^{2} -2t^{3}

at t = 5s

x = 14*5^{2} -2*5^{3} = 14*25 - 2*125 = 350 - 250 = 100 m

b) v = \frac{dx}{dt}

       = 28t - 6t^2

at t = 5 s

v = 28*5-6*25 = 140 - 150 = -10 m/s

c) a = \frac{dv}{dt}

     = 28 - 12t

at t = 5 s

a = 28 -12*5= 28-60= -32 m/s^2

d) At maximum positive coordinate velocity = 0

So, 0 = 28t - 6t^2

         t = \frac{28}{6} = \frac{14}{3} = 4.66 s

  At t = 4.66 s

   X = 14 * 4.66^2 - 2* 4.66^3 = 202.39  m

e) At t = 4.66 s

f) At maximum positive velocity a = 0

   0=28-12t

   t = \frac{28}{12} = \frac{7}{3} = 2.33 s

At t = 2.33 s

V = 28*2.33- 6*2.33^2= 32.67 m/s

g) t = 2.33 s

h) When particle is not moving v = 0

So 0= 28t - 6 t^2

 t = \frac{28}{6} = 4.66 seconds

At t = 4.66 s

a = 28 - 12 * 4. 66 = -27.93m/s^2

i) At t = 0s, X =0m

       t = 5s, X = 100m

So, Displacement = 100m

Velocity = \frac{Displacement}{Time}  = \frac{100}{5} = 20m/s

8 0
3 years ago
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