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4 years ago

Birds, squirrels, and chipmunks all living in the same tree, using the same resources, are an example of:

Physics

1 answer:

Ulleksa [173]4 years ago

4 0

Explanation :

In Interspecific competition, different individuals of different species fight for the same resource in an ecosystem. The resources can be food or living space.

Birds belong to the group of aves, squirrels and chipmunks are from the family of Sciuridae.

All three are from different species. They are on the same ecosystem i.e. tree. They form the interspecific competitions.

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An element has a charge of -3, has 8 protons, 11 neutrons, and electrons

Sati [7]

Question isn’t clear
If it’s asking the no of electrons then -
No of electrons =no of protons in an atom of a element ....therefore there are 11 electrons

6 0

3 years ago

A circular area with a radius of 6.50 cm lies in the xy-plane. What is the magnitude of the magnetic flux through this circle du

White raven [17]

Answer:

$a. \phi _B=3.0528\times10^-^3T\ m^2\\ \\b. \phi_B=1.83299\times10^-^3T\ m^2\\\\c.\phi_B=0$

Explanation:

#Consider a circular area of radius $R=2.98cm$ in the xy-plane at z=0. This means all the are vector points toward the +ve z-axis.

a. first, find the magnetic flux if the magnetic field has a magnitude of $B=0.23T$ and points toward the +ve z-axis. The angle between the magnetic field and the area is $\theta=0$ . Hence the magnetic flux:-

$\phi _B=\int {\bar B} . d\bar A \\=\int BdAcos(\theta)=BAcos(0)=BA\\\\=\pi R^2B=\pi(6.50\times10^-^3m)^2(0.230T)\\=3.0528\times10^-^3 T\ m^2$

Hence flux magnitude in $+z$ direction is $3.0528\times10^-^3T \ m^2$

b. We now find the magnetic flux when the field has a magnitude of B=0.230T and points at an angle of $\theta=53.1\textdegree$ from the $+z$ direction.

Magnetic flux is calculated as:

$\phi _B=\int\bar B \bar dA\\=\int BdAcos (\theta)=BAcos(0)=BA\\=\pi R^2B=\pi(6.50\times 10^-^2m)^2(0.230T)\\=1.83299\times 10^-^3 T \ m^2$

Hence the flux at an angle of $53.1\textdegree$ is $1.83299\times 10^-^3T \ m^2$

c. We now need to find the magnetic flux if the field has a magnitue of B=0.230T and points in the direction of +y-direction. As with the previous parts, the magnetic flux will be calculated as:

$\phi_B= \int\bar B \times d\bar A\\=\int BdAcos(\theta)\\=BAcos(90\textdegree)\\=0$

Hence the magnetic flux in the +y-direction is zero.

3 0

3 years ago

A machine lifts a 35 kg object doing 6860 J worth of work. How much power is produced by the machine if it lifts the object in 4

timofeeve [1]

Answer:

Explanation:

We need the power equation for this which is

P = Work/time

We have everything we need to solve this (the mass of the object is extra information):

P = 6860/4

P = 1715W

5 0

3 years ago

A hockey puck with a mass of 0.175 kg slides over the ice. The puck initially slides with a speed of 5.25 m/s, but it comes to a

Neko [114]

Answer:

1.70 J

Explanation:

The heat dissipated is the difference in the kinetic energies.

This is given by

$E = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2$

$v_i$ and $v_f$ are the initial and final velocities.

With m = 0.175 kg,

$E = \frac{1}{2}\times0.175(2.85^2 - 5.25^2) = -1.701\text{ J}$

The negative sign appears because energy is lost.

7 0

3 years ago

Electrostatic precipitator in chimneys of factories and hybrid vehicle technology can help in curbing air pollution. How? plzzzz

nexus9112 [7]

It helps reduce the amount of carbon emissions released into the air
An electrostatic precipitator is a filtration device that removes fine particles, like dust and smoke, from a flowing gas using the force of an induced electrostatic charge minimally impeding(slowing down) the flow of gases through the unit.

a device for removing small particles, as of smoke, dust, or oil, from a gas, as air, by passing the gas first through an electrically charged screen that gives a charge to the particles, then between two charged plates where the particles are attracted to one surface.
http://www.britannica.com/technology/electrostatic-precipitator

7 0

3 years ago