Answer: y = -2/3(x-3)^2 + 0 or y = -2/3(x-3)^2
Step-by-step explanation:
vertex form is y=a(x-h)^2 + k
here we can see the vertex is (3,0) which is (x,y). Or (h,k) in this case.
so to plug that into vertex form, we now have y=a(x-3)^2 + 0. or just y=a(x-3)^2.
now we need to find "a" which is the leading coefficient. to do that we can plug in the (6,-6) for the x and y parts of the above equation. so we'd have
-6=a(6-3)^2. which goes to -6=a(2)^2 which is -6=4a. divide each side by 4 to get a = -2/3. plug this in for a
the final equation would be y = -2/3(x-3)^2 + 0 or y = -2/3(x-3)^2
Answer:

Step-by-step explanation:
Slope-Intercept Form: y = mx + b
Slope: 
Y-Intercept: 

D. Any item that maintains its worth over time. Plz mark Brainliest
angle 1 = 180° - 115° (Linear Pair)
<u>angle 1 = 65°</u>
<u>angle 2 = angle 1 = 65°</u> ( Angles on the equal sides of an isosceles triangle )
angle 3 = 180° - (65° + 65°) (Angle Sum Property)
angle 3 = 180° - 130°
<u>angle</u><u> </u><u>3</u><u> </u><u>=</u><u> </u><u>5</u><u>0</u><u>°</u>
angle 4 = 180° - 65° (Linear Pair)
<u>angle</u><u> </u><u>4</u><u> </u><u>=</u><u> </u><u>1</u><u>1</u><u>5</u><u>°</u>
<u>angle</u><u> </u><u>5</u><u> </u><u>=</u><u> </u><u>1</u><u>1</u><u>5</u><u>°</u> (Vertically Opposite Angles)