Answer:
V = 346.15 Volts
Explanation:
Given that,
Diameter of the sphere, d = 0.390 cm
Radius, r = 0.195 cm
Charge,
The electric potential near its surface is given by :
So, the potential near its surface is equal to 346.15 V.
vf^2 = 2ad
vf^2 = 2(9.81)(44m)
vf^2 = 863.28
vf = √863.28
vf = 29.4 - using equations of motion
ME = PE + KE
ME = mgh + 1/2mv^2
ME = (1)(9.81)(44) + 1/2(1)(3^2)
ME = 431.64 + 4.5
ME = 436.14 - using conservation of energy
hope this helps :)
1. b An element is the simplest form of a substance.
3. a Atoms are comprised of particles such as protons, neutrons, and electrons.
2. c Atoms are tiny pieces of matter.
4. d Phase refers to the state of matter: gas, liquid, and solid.
Well you could drive stakes or piers down into the bedrock to anchor it, but you would still need to be cautious of erosion.