Heat is distributed through the atmosphere by winds<br> True<br><br> False

A 1.5kg cannon is loaded with a 0.52 kg ball . The cannon is ignited and launches the ball forward with speed of 75m/s. Determin

Mila [183]

Answer:

-26 m/s (backward)

Explanation:

We can solve this problem by using the law of conservation of momentum.

In fact, the total momentum momentum of the cannon + ball system must be conserved before and after the explosion.

Before the explosion, they are both at rest, so the total momentum is zero:

p = 0

After the explosion, the total momentum is:

$p=MV+mv$

where

M = 1.5 kg is the mass of the cannon

m = 0.52 kg is the mass of the ball

v = +75 m/s is the velocity of the ball

V is the velocity of the cannon

Since the momentum is conserved, we can equate the two expressions:

$0=MV+mv$

And solving, we find V:

$V=-\frac{mv}{M}=-\frac{(0.52)(+75)}{1.5}=-26 m/s$

where the negative sign means the direction is opposite to that of the ball.

4 0

4 years ago

To test your FHE brother's claims about his car, you accept his offer of a ride about campus. Not wanting to exceed the speed li

damaskus [11]

Answer:

4.78 m/s^2

Explanation:

A)From he FBD

we can write

Tcosθ= mg

Tsinθ= ma

dividing we get tanθ= a/g

a= g tanθ

a= 9.81 tan26°= 4.78 m/s^2

7 0

4 years ago

25% part (c) assume that d is the distance the cheetah is away from the gazelle when it reaches full speed. Derive an expression

levacccp [35]

maximum speed of cheetah is

$v_1 = v_{max}$

speed of gazelle is given as

$v_2 = v_{g}$

Now the relative speed of Cheetah with respect to Gazelle

$v_{12} = v_1 - v_2$

$v_{12} = v_{max} - v_g$

now the relative distance between Cheetah and Gazelle is given initially as "d"

now the time taken by Cheetah to catch the Gazelle is given as

$d = v_{12}* t$

so by rearranging the terms we can say

$t = \frac{d}{v_{12}}$

$t = \frac{d}{v_{max} - v_g}$

so above is the relation between all given variable

6 0

4 years ago

I need help plz ITS A QUIZZZZZZZZZZZZZZZZZZZ

zmey [24]

Answer:

B

Explanation:

6 0

3 years ago

Jim rode at an average speed of 12mph in 2 hours the he walked at an average of speed of 3 mph 0.5 hours what was the total dist

mrs_skeptik [129]

Answer:

12mph in 2hrs and 3mph in 0.5hrs the total distance would be 12*2 and 3*0.5 which would be 24 and 1.5 so we add those 24+1.5= 25.5. The answer would be 25.5

6 0

4 years ago

Heat is distributed through the atmosphere by winds True False