An airplane leaves New York to fly to Boston it travels 1000 KM in two hours what is the average speed of the airplane

Novay_Z [31]

The problem was too big to type in my phone.

I hope my answer is readable.

P.S After the collision P is also moving in the same direction as Q.

5 0

4 years ago

A hot-air balloon of diameter 12 mm rises vertically at a constant speed of 14 m/s. A passenger accidentally drops his camera fr

fgiga [73]

Answer:

The balloon is 66.62 m high

Explanation:

Combined Motion

The problem has a combination of constant-speed motion and vertical launch. The hot-air balloon is rising at a constant speed of 14 m/s. When the camera is dropped, it initially has the same speed as the balloon (vo=14 m/s). The camera has an upward movement for some time until it runs out of speed. Then, it falls to the ground. The height of an object that was launched from an initial height yo and speed vo is

$\displaystyle y=y_o+v_o\ t-\frac{g\ t^2}{2}$

The values are

$\displaystyle y_o=15\ m$

$\displaystyle v_o=14\ m/s$

We must find the values of t such that the height of the camera is 0 (when it hits the ground)

$\displaystyle y=0$

$\displaystyle y_o+v_o\ t-\frac{g\ t^2}{2}=0$

Multiplying by 2

$\displaystyle 2y_o+2v_ot-gt^2=0$

Clearing the coefficient of $t^2$

$\displaystyle t^2-\frac{2\ V_o}{g}\ t-\frac{2\ y_o}{g}=0$

Plugging in the given values, we reach to a second-degree equation

$\displaystyle t^2-2.857t-3.061=0$

The equation has two roots, but we only keep the positive root

$\displaystyle \boxed {t=3.69\ s}$

Once we know the time of flight of the camera, we use it to know the height of the balloon. The balloon has a constant speed vr and it already was 15 m high, thus the new height is

$\displaystyle Y_r=15+V_r.t$

$\displaystyle Y_r=15+14\times3.69$

$\displaystyle \boxed{Y_r=66.62\ m}$

3 0

3 years ago

A projectile is launched from the ground at an angle of 60o above the horizontal. At what point in its trajectory does it have t

Elodia [21]

Answer:

It's constant everywhere in its trajectory.

Explanation:

the projectile was launched with an initial velocity, the only acceleration that is affecting the projectile's velocity is gravity.

The acceleration of gravity is practically equal everywhere on earth, so during its trajectory, we have to take into consideration only the acceleration because of gravity.

This is only correct because the projectile was launched with an initial velocity and it's not accelerating from rest and then falls.

5 0

3 years ago

A mass of 5 kg is moving at 5 m/s when it collides with another mass of 2 kg moving in the same direction at 2 m/s. After the co

Burka [1]

Answer:

4.14 m/s

Explanation:

m¹u¹+m²u²=(m¹+m²)v

5(5)+2(2)=(5+2)v

25+4=7v

29=7v

29/7=v

v=4.14 m/s

3 0

4 years ago

What is the value of x? 6x−2(x 4)=12

Ymorist [56]

Answer: The value of x is -6.

Explanation:

To calculate the value of 'x', we need to solve each function happening inthe equation.

The equation provided to us is $6x-2(4x)=12$

To solve this, we will multiply 4x with 2 and then subtract the like terms and finally, we evaluate the value of 'x'.

$6x-8x=12\\\\-2x=12\\\\x=\frac{12}{-2}\\\\x=-6$

Hence, the value of x will be -6.

5 0

3 years ago

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An airplane leaves New York to fly to Boston it travels 1000 KM in two hours what is the average speed of the airplane￼

An airplane leaves New York to fly to Boston it travels 1000 KM in two hours what is the average speed of the airplane