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3 years ago

2.8 to 3.6 Find the ratio to the first # To the 2nd #

Mathematics

1 answer:

Jlenok [28]3 years ago

3 0

Answer:

1:4 & 1:2

Step-by-step explanation:

divide first set by 2 a piece and the second by 3

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Multiple Choice: Choose the correct answer for questions 1 and 2.

pickupchik [31]

Answer:

The correct answer is:

C. Trisha is shorter than 75% of girls aged 16 to 18.

Step-by-step explanation:

When a dataset is divided into four equal parts, the first part is called the lower quartile. The data is usually sorted in ascending order before finding quartiles.

The lower quartile contains 25% of the whole data. The values in lower quartile are are less than 75% of the values.

If Trisha's height is in lower quartile that means her height is less than the girls in middle and higher quartile.

Hence,

The correct answer is:

C. Trisha is shorter than 75% of girls aged 16 to 18.

4 0

3 years ago

Evaluate each expression for the given value (please answer all)

Anna [14]

Answer:

-20a - 65 = -104 for a = 2.7

-6x + 52 = 45 for x = 1 1/6

Step-by-step explanation:

-20a - 50 for a = 2.7

Insert 2.7 in for a.

-20(2.7) - 50 = -54 - 50 = -104

-6x + 52 for x = 1 1/6

Insert 1 1/6 for x.

-6(1 1/6) + 52 = -7 + 52 = 45

8 0

3 years ago

Darin has a rectangular vegetable garden. It is 5 yards long and 8 feet wide.

Lelu [443]

Answer:

about 15.328 yrds

Step-by-step explanation:

two sides are 5 yrds, so 5+5= 10yrds. two sides are 8 ft, 8+8=16 ft. there are .3333 yrds in 1 foot so 16*.3333 = about 5.328yrds

10+5.328 = 15.328

7 0

3 years ago

3 (4x + 7) = 43; 12x + 21 = 43

777dan777 [17]

Answer:

Distributive property

Explanation:

You are distributing the 3 to the parenthesis to get 12x+21 =43

6 0

3 years ago

Read 2 more answers

in a standard casino dice game the roller wins on the first roll if he rolls a sum of 7 or 11. what is the probability of winnin

Alborosie

Answer-

The probability of winning on the first roll is 0.22

Solution-

As in the game of casino, two dice are rolled simultaneously.

So the sample space would be,

$|S|=6^2=36$

Let E be the event such that the sum of two numbers are 7, so

E = {(1,6), (2,5), (3,4), (4,3), (5,2), (6,1)}

$|E|=56$

$\therefore P(E)=\dfrac{|E|}{|S|}=\dfrac{6}{36}$

Let F be the event such that the sum of two numbers are 11, so

F = {(6,5), (5,6)}

$|F|=2$

$\therefore P(F)=\dfrac{|F|}{|S|}=\dfrac{2}{36}$

Now,

$P(\text{sum is 7 or 11)}=P(E\ \cup\ F)=P(E)+P(F)=\dfrac{6}{36}+\dfrac{2}{36}=\dfrac{8}{36}=\dfrac{2}{9}=0.22$

8 0

3 years ago