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Dmitriy789 [7]
4 years ago
9

A phone plan costs $29.99 per month and includes 200 minutes of calling time. Minutes over 200 are charged at a rate of 25 cents

per minute. If the phone was used for 357 minutes one month, how much was the bill?
Mathematics
1 answer:
mylen [45]4 years ago
5 0

Step-by-step explanation:

357-200 is 157 extra minutes (we are only counting the extra minutes)

157*0.25 is 39.25 (this is how much is the extra minutes in total cost)

therefore, add 39.25 and 29.99

29.99+39.25 is 62.24

Therefore, the total bill was $62.24

hope this helps :)

Have a nice day !

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Misha Larkins [42]
1. you have to figure out what 3/4 of Ella's time is.
1 \frac{3}{5}  =  \frac{8}{5}
(You find that out by multiplying 5x1. Then add 3.)
2. Convert the fractions into decimals. (This will help make it easier when dividing.)
\frac{8}{5}  = 8 \div 5 = 1.6
\frac{3}{4}  = 3 \div 4 = .75
3. Next you are going to divide 1.6 by .75
1.6 \div .75 = 2.13
4. Now multiple 2.13 by 5.
2.13 \times 5 = 10.65
Answer is 10

3 0
3 years ago
Can not be bothered to write the question so ima just attach it
stellarik [79]

Use desmos graphing calculator, for visuals. It's easy to use as well.

A is 0 (zero)

(1x1 + 2x1 - 3)

B) D ( lies on 1 on our x-axis)

C) This tells you to draw a line at zero on the y-axis, a horizontal line BTW & read off the x values, where the line touches the pink graph/diagram.

y=x^2+2x-3 is the similar to x^2+2x-3=0 because the letter y now represents zero. So, that's why we draw the line y=0 (a horizontal line at zero). Then, use it to find the x values.

Thus, x = - 3 & x = 1

Hope this helps!

6 0
2 years ago
A university found that of its students withdraw without completing the introductory statistics course. Assume that students reg
polet [3.4K]

Answer:

A university found that 30% of its students withdraw without completing the introductory statistics course. Assume that 20 students registered for the course.

a. Compute the probability that 2 or fewer will withdraw (to 4 decimals).

= 0.0355

b. Compute the probability that exactly 4 will withdraw (to 4 decimals).

= 0.1304

c. Compute the probability that more than 3 will withdraw (to 4 decimals).

= 0.8929

d. Compute the expected number of withdrawals.

= 6

Step-by-step explanation:

This is a binomial problem and the formula for binomial is:

P(X = x) = nCx p^{x} q^{n - x}

a) Compute the probability that 2 or fewer will withdraw

First we need to determine, given 2 students from the 20. Which is the probability of those 2 to withdraw and all others to complete the course. This is given by:

P(X = x) = nCx p^{x} q^{n - x}\\P(X = 2) = 20C2(0.3)^2(0.7)^{18}\\P(X = 2) =190 * 0.09 * 0.001628413597\\P(X = 2) = 0.027845872524

P(X = x) = nCx p^{x} q^{n - x}\\P(X = 1) = 20C1(0.3)^1(0.7)^{19}\\P(X = 1) =20 * 0.3 * 0.001139889518\\P(X = 1) = 0.006839337111

P(X = x) = nCx p^{x} q^{n - x}\\P(X = 0) = 20C0(0.3)^0(0.7)^{20}\\P(X = 0) =1 * 1 * 0.000797922662\\P(X = 0) = 0.000797922662

Finally, the probability that 2 or fewer students will withdraw is

P(X = 2) + P(X = 1) + P(X = 0) \\= 0.027845872524 + 0.006839337111 + 0.000797922662\\= 0.035483132297\\= 0.0355

b) Compute the probability that exactly 4 will withdraw.

P(X = x) = nCx p^{x} q^{n - x}\\P(X = 4) = 20C4(0.3)^4(0.7)^{16}\\P(X = 4) = 4845 * 0.0081 * 0.003323293056\\P(X = 4) = 0.130420974373\\P(X = 4) = 0.1304

c) Compute the probability that more than 3 will withdraw

First we will compute the probability that exactly 3 students withdraw, which is given by

P(X = x) = nCx p^{x} q^{n - x}\\P(X = 3) = 20C3(0.3)^3(0.7)^{17}\\P(X = 3) = 1140 * 0.027 * 0.002326305139\\P(X = 3) = 0.071603672205\\P(X = 3) = 0.0716

Then, using a) we have that the probability that 3 or fewer students withdraw is 0.0355+0.0716=0.1071. Therefore the probability that more than 3 will withdraw is 1 - 0.1071=0.8929

d) Compute the expected number of withdrawals.

E(X) = 3/10 * 20 = 6

Expected number of withdrawals is the 30% of 20 which is 6.

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Step-by-step explanation:

Given the information:

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1/ x^{2} = 12

<=> x = 2\sqrt{3}

2/ a^{2} = 24

<=> a = 2\sqrt{6}

Please have a look at the attached photo.

Hope it will find you well.

6 0
3 years ago
Which of the following is positive? -(-31), -(31), -31, 0-31
BartSMP [9]
It would be -(-31) because a negative and negative is a positive
3 0
4 years ago
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