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puteri [66]
3 years ago
8

I WILL GIVE BRILLIANTS

Mathematics
1 answer:
Phoenix [80]3 years ago
8 0

(1) 34.8 liters

(2) $63.55

Solution:

(1) There is a mistake in question. It is 42 liters.

Total gasoline a car can hold = 42 liters

Liters of gasoline filled in beginning of the week = 35.8

Liters of gasoline used during the week = 28.6

Remaining liters of gasoline in the tank = 35.8 – 28.6

                                                                  = 7.2 liters

Quantity of gasoline need to buy to fill the tank completely

                               = Total capacity – Remaining gas in the tank

                               = 42 liters – 7.2 liters

                               = 34.8 liters

Hence Alberto need to buy 34.8 liters of gasoline to fill the tank.

Option B is the correct answer.

(2)

Shamika earns in first week = $25.75

Shamika earns in next week = $37.80

Total money Shamika have = First week earning + Second week earning

                                              = $25.75 + $37.80

                                              = $63.55

Don't add or subtract spending money, because the question is how much she have from these two weeks.

Hence Shamika have $63.55 from these two weeks.

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Answer:

Step-by-step explanation:

So you start with 5.7 miles which is the first ride and the long ride is 5 2/3 times longer so you multiply 5.7 by 5 2/3. 5.7 is equivalent to 5 7/10 so you multiply 5 7/10 by 5 2/3. If we get common denominators we will end up with 5 21/30 and 5 20/30 then you multiply. You will get 32.3: 32.3 is equivalent to 32 and 3/10. Then you add that to 5 and 7/10. You will get 38.

Answer: 38

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3 years ago
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The quadratic function g(x) = a.ca + bx+c has the
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<em>The value of b is 14 and the value of c is 65</em>

<h2>Explanation:</h2>

The quadratic function is a function of the form:

f(x)=ax^2+bx+c

Here we know that the leading coefficient a=1 so we reduce our equation to:

g(x)=x^2+bx+c

The roots are those values at which g(x)=0

So:

x^2+bx+c=0 \\ \\ First \ root: \\ \\ (-7+4i)^2+b(-7+4i)+c=0 \\ \\ (-7)^2-2(7)(4i)+(4i)^2-7b+4bi+c=0 \\ \\  49-56i+16i^2-7b+4bi+c=0 \\ \\ \\ Simplifying: \\ \\ 49-56i+16(-1)-7b+4bi+c=0 \\ \\ 49-56i-16-7b+4bi+c=0 \\ \\ 33-56i-7b+4bi+c=0 \\ \\ \\

Second \ root: \\ \\ (-7-4i)^2+b(-7-4i)+c=0 \\ \\ (-1)^2(7+4i)^2+b(-7-4i)+c=0 \\ \\ (7)^2+2(7)(4i)+(4i)^2-7b-4bi+c=0 \\ \\  49+56i+16i^2-7b-4bi+c=0 \\ \\ \\ Simplifying: \\ \\ 49+56i+16(-1)-7b-4bi+c=0 \\ \\ 49+56i-16-7b-4bi+c=0 \\ \\ 33+56i-7b-4bi+c=0

So we have:

(1) \ 33-56i-7b+4bi+c=0 \\ \\ (2) \ 33+56i-7b-4bi+c=0 \\ \\ \\ Subtract \ 2 \ from: \\ \\ 33-56i-7b+4bi+c-(33+56i-7b-4bi+c)=0 \\ \\ 33-56i-7b+4bi+c-33-56i+7b+4bi-c=0 \\ \\ \\ Combine \ like \ terms: \\ \\ 33-33-56i-56i-7b+7b+4bi+4bi+c-c=0 \\ \\ -112i+8bi=0 \\ \\ Isolating \ b: \\ \\ b=\frac{112i}{8i} \\ \\ \boxed{b=14}

Finding c from (1):

33-56i-7b+4bi+c=0 \\ \\ \\ Substituting \ b: \\ \\ 33-56i-7(14)+4(14)i+c=0 \\ \\ 33-56i-98+56i+c=0 \\ \\ -65+c=0 \\ \\ \boxed{c=65}

<h2>Learn more:</h2>

Complex conjugate: brainly.com/question/2137496

#LearnWithBrainly

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