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3 years ago

5. How many Earths could fit between the Earth and the sun?

1 answer:

5 0

12000
You need to multiply the size of the Earth and 12000
Once you do that you get the distance between the Earth and the Sun

You might be interested in

Which is a diatomic molecule?<br><br> A)He<br><br> B)O2<br><br> C)NaCl<br><br> D)CuF2

Alona [7]

B is the correct answer

5 0

3 years ago

What is the ph category of each of the following i need help plz

shepuryov [24]

1. base

2. neutral

3. acid

4. base

If this is what you meant, hope it helps

4 0

3 years ago

2. Calculate how many moles of H2 would be produced if 0.250 mol of Fe reacts completely. (1 mark)

den301095 [7]

Hey there!:

Balanced Equation , for the reaction:

3 H₂SO₄(aq) + 2 Fe(s) → Fe₂(SO₄)₃(aq) + 3 H₂(g)

2 moles Fe ---------------------------------- 3 moles H₂

0.250 moles Fe ---------------------------- ( moles H₂ ) ??

____________________________________________

moles H₂ = 0.250 × 3 / 2

moles H₂ = 0.75 / 2

moles = 0.375 moles of H₂

Hope this helps!

7 0

3 years ago

At what temperature does a gas at 1.00 atm and 20 degree Celsius have a pressure of 4.00 atm.

vfiekz [6]

Answer:

P1 =4 atm

T1= 20°C

P2=1 atm

T2=?

According to Gay-Lussac's Law or Third Gas Law,

P1T2=P2T1

4×T2=1×20

T2= 20/4

T2= 5°C

Answer At 5°C temperature does a gas at 1.00 atm !

7 0

3 years ago

What is the maximum mass, in kilograms, of (NH4)2U2O7 that can be formed from the reaction of 100 kg of water and 100 kg of ammo

V125BC [204]

Mass of (NH₄)₂U₂O₇ : 410.05 kg

<h3>Further explanation</h3>

Reaction

2UO₂SO₄ + 6NH₃ + 3H₂O → (NH₄)₂U₂O₇ + 2(NH₄)₂SO₄

MW UO₂SO₄ : 366.091

MW (NH₄)₂U₂O₇ : 624.131

MW H₂O : 18.0153

MW NH₃ : 17.0306

mol of 100 kg water :

$\tt \dfrac{100}{18.0153}=5.55$

mol of 100 kg ammonia :

$\tt \dfrac{100}{17.036}=5.87$

mol of UO₂SO₄ :

$\tt \dfrac{481}{366.091}=1.314$

Limiting reactants : smallest mol ratio(mol : coefficient)

$\tt \dfrac{5.55}{3}\div \dfrac{5.87}{6}\div \dfrac{1.314}{2}=1.85\div 0.98\div 0.657$

UO₂SO₄ ⇒ Limiting reactants

mol (NH₄)₂U₂O₇ : mol UO₂SO₄

$\tt \dfrac{1}{2}\times 1.314=0.657$

mass (NH₄)₂U₂O₇

$\tt 0.657\times 624.131=410.05$

5 0

3 years ago