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Furkat [3]
3 years ago
15

If a person did overshoot the endpoint, would this cause the experimental value for the % of acid in vinegar to be too high or t

oo low? Explain.
Chemistry
1 answer:
Stels [109]3 years ago
7 0
OHHHHHHHHH MYYYYYYYYYYYYY GOOOOOOODDDDDDDDDDDD

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A 45.7 block of an unknown metal at 74.2 °C is placed in 72.9 g of water at 15.9 °C. If the
g100num [7]

Answer:

0.934J/g°C

Explanation:

Using Q = mc∆T

However, in this question;

(Q)water = -(Q)metal

(mc∆T)water = -(mc∆T)metal

According to the information provided in the question;

For water;

m = mass = 72.9g

c = specific capacity of water = 4.184 J/g°C

∆T = 22.9 - 15.9 = 7°C

For metal;

m = mass = 45.7g

c = specific capacity of water = ?

∆T = 22.9 - 72.9 = -50°C

(mc∆T)water = -(mc∆T)metal

(72.9 × 4.184 × 7) = -(45.7 × c × -50)

2135.0952 = -(-2285c)

2135.0952 = 2285c

c = 2135.0952/2285

c of metal = 0.934J/g°C

3 0
2 years ago
Number of moles of Sn (l) produced when 4.0 moles of H2 (g) is completely consumed
Dafna11 [192]
The answer is 2.0 moles.
From their coefficients in the balanced chemical equation below for the reaction of tin dioxide with hydrogen gas to produce tin and water:
     SnO2(s) + 2H2(g) ==>Sn(l) + 2H2O(g)
two moles of hydrogen gas is to produce one mole of tin. We use this mole ratio to compute for the number of moles of tin as:
     moles of Sn = 4.0mol H2 (1mol Sn/2mol H2) = 2.0 mol
4 0
3 years ago
Which of the following is the correct calculation for determining the density of an object with a mass of 54 g and a volume of 6
RSB [31]

Answer:

\rho =9g/mL

Explanation:

Hello,

In this case, since the density is computed via the division of the mass by the volume:

\rho =\frac{m}{V}

For the given mass of 54 g and volume of 6 mL, the density turns out:

\rho =\frac{54g}{6mL}\\ \\\rho =9g/mL

Best regards.

3 0
2 years ago
When vinegar and baking soda are combined what bubbles form
natka813 [3]
The bubbles are Carbon dioxide gas
5 0
3 years ago
17. Is the scientific method suitable for solving problems only in<br> the sciences? Explain.
Neporo4naja [7]

Answer:

Hey mate

Explanation:

Yes these methods are only used in biology, chemistry, physics, geology and physcology.... They can't be used in maths or other subject, as it is said SCIENCE IS SCIENCE!

Hope it helps you,

mark me the brainliest,

follow me

6 0
2 years ago
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