3 years ago

An exit sign must be

Engineering

1 answer:

Volgvan3 years ago

7 0

Answer:

A exit sign must be a way out of a place or in.And must be illuminated to be seen.Hope it helps:)

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A tensile test uses a test specimen that has a gage length of 50 mm and an area = 206 mm2. During the test, the specimen yields

vampirchik [111]

Answer:

The percent elongation in the length of the specimen is 42%

Explanation:

Given that:

The gage length of the original test specimen $L_o$ = 50 mm

The final gage length $L_f$ = 71 mm

The area = 206 mm²

maximum load = 162,699 N

To determine the percent elongation in %, we use the formula:

$\%EL = \dfrac{L_f-L_o}{L_o}\times 100$

$\%EL = \dfrac{71 \ mm-50 \ mm}{50 \ mm}\times 100$

$\%EL = \dfrac{21 mm}{50 \ mm}\times 100$

$\%EL = 0.42 \times 100$

$\mathbf{\%EL = 42 \%}$

The percent elongation in the length of the specimen is 42%

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You are given a body with no body forces and told that the stress state is given as: ⎡ ⎣ 3αx 5βx2 + αy γz3 5βx2 + αy βx2 0 γz3 0

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Answer:

This doesn't represent an equilibrium state of stress

Explanation:

∝ = 1 , β = 1 , y = 1

x = 0 , y = 0 , z = 0 ( body forces given as 0 )

Attached is the detailed solution is and also the conditions for equilibrium

for a stress state to be equilibrium all three conditions has to meet the equilibrum condition as explained in the attached solution

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