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kirill115 [55]
2 years ago
8

Determine the number of protons and neutrons in plutonium-239 and write its symbol in the form azx.

Chemistry
2 answers:
devlian [24]2 years ago
6 0

Explanation:

Atomic number of an atom means the sum of total number of protons present in an atom.

Mass number is the sum of total number of protons and neutrons present in an atom.

And, when we write the symbol of an atom then it is represented like this ^{a}_{z}X, where "a" represents the mass number of the atom and "z" represents the number of protons.

Therefore, in plutonium-239 it is shown that mass number is 239 and atomic number of a plutonium atom is 94. Now, calculate its number of neutrons as follows.

         Mass number = no. of protons + no. of neutrons

                 239 = 94 + no. of neutrons

           no. of neutrons = 239 - 94

                                      = 145

Thus, we can conclude that in plutonium-239 number of protons is 94, number of neutrons is 145 and its symbol is ^{239}_{94}Pu.

Verizon [17]2 years ago
4 0
94 protons and 145 neutrons
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How are the properties of sodium chloride different than sodium and chlorine
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3 years ago
What is the pH at the equivalence point in the titration of a 25.7 mL sample of a 0.370 M aqueous nitrous acid solution with a 0
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Answer:

pH = 8.24

Explanation:

Nitrous acid (HNO₂) reacts with KOH, thus:

HNO₂ + KOH → KNO₂ + H₂O

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0.0257mL ₓ (0.370mol / L) = 0.00951moles.

In equivalence point, the complete moles of nitrous acid reacts with KOH producing potassium nitrite. There are needed:

0.00951mol ₓ (1L / 0.491mol) = 0.01937L ≡ 19.4mL of 0.491M KOH to reach equivalence point.

Total volume in equivalence point is: 19.4mL + 25.7mL = <em>45.1mL</em>

Potassium nitrite is in equilibrium with water, thus:

NO₂⁻ + H₂O ⇄ HNO₂ + OH⁻

Where equilibrium constant, Kb, is defined as:

Kb = 1.41x10⁻¹¹ = \frac{[OH^-][HNO_2]}{[NO_2]}

In equilibrium, molarity of each compound are:

[NO₂⁻]: 0.00951mol/0.00451L - X = 0.211M - X

[HNO₂]: X

[OH⁻]: X

<em>Where X is reaction coordinate</em>

Replacing in Kb:

1.41x10⁻¹¹ = \frac{[X][X]}{[0.211 -X]}

0 = X² + 1.41x10⁻¹¹X - 2.97x10⁻¹²

Solving for X:

X = -1.72x10⁻⁶ <em>FALSE ANSWER. There is no negative concentrations.</em>

X = 1.72x10⁻⁶. <em>Right answer.</em>

That means:

[OH⁻]: 1.72x10⁻⁶M

As pOH is -log [OH⁻] and pH = 14-pOH:

pOH = 5.76; <em>pH = 8.24</em>

3 0
3 years ago
There are two beakers that contain the same liquid substance at the same temperature. The larger beaker is 1,000ml and the small
azamat

Answer:

Answer choice B

Explanation:

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