The mass, in grams, of the sample of methanol (CH₃OH) is 64 grams.
<h3>How we calculate mass from moles?</h3>
Mass of any substance can be calculated by using moles as:
n = W/M, where
W = required mass
M = molar mass
In the question that:
Moles of methanol = 2mole
Molar mass of methanol = 32g/mole
On putting these values in the above equation, we get
W = n × M
W = 2mole × 32g/mole = 64g
Hence, 64 grams is the mass of the sample.
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brainly.com/question/15374113
30. mixture of compounds
31. compound
32. element
33. compound
34. compound
34. mixture of elements and compounds
The answer is B. Each chlorine has three non-bonded pairs and one bonded pair of electrons.
I just took the test and it was correct! 5/5 :)
Answer:
1. Balanced chemical for the given chemical reaction is :

number of mole of sulphuric acid produced = 12.5 mol
number of mole of oxygen required=6.25 mol
Explanation:
1. Balanced chemical for the given chemical reaction is :

from above balanced equation it is clearly that ,
2 mole of sulpher dioxide gives 2 mole of sulphuric acid
1 mole of sulpher dioxide gives 1 mole of sulphuric acid
therefore,
12 .5 mole of sulpher dioxide will givs 12.5 mole of sulphuric acid
number of mole of sulphuric acid produced = 12.5 mol
2 mole of sulphur dioxide needs 1 mole of oxygen gas
so,
1 mole of sulphur dioxide needs 0.5 mole of oxygen gas
therefore 12.5 of sulphur dioxide needs
mole of oxygen
number of mole of oxygen required=6.25 mol