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3 years ago

Determine the number of protons and neutrons in plutonium-239 and write its symbol in the form azx.

Chemistry

2 answers:

devlian [24]3 years ago

6 0

Explanation:

Atomic number of an atom means the sum of total number of protons present in an atom.

Mass number is the sum of total number of protons and neutrons present in an atom.

And, when we write the symbol of an atom then it is represented like this $^{a}_{z}X$ , where "a" represents the mass number of the atom and "z" represents the number of protons.

Therefore, in plutonium-239 it is shown that mass number is 239 and atomic number of a plutonium atom is 94. Now, calculate its number of neutrons as follows.

Mass number = no. of protons + no. of neutrons

239 = 94 + no. of neutrons

no. of neutrons = 239 - 94

= 145

Thus, we can conclude that in plutonium-239 number of protons is 94, number of neutrons is 145 and its symbol is $^{239}_{94}Pu$ .

Verizon [17]3 years ago

4 0

94 protons and 145 neutrons

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Answer:

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Explanation:

According to Arrhenius equation- $k=Ae^{\frac{-E_{a}}{RT}}$ , where k is rate constant, A is pre-exponential factor, $E_{a}$ is activation energy, R is gas constant and T is temperature in kelvin scale.

As A is identical for both peptide therefore-

$\frac{k_{ala-pro}}{k_{phe-pro}}=e^\frac{[E_{a}^{phe-pro}-E_{a}^{ala-pro}]}{RT}$

Here $\frac{k_{ala-pro}}{k_{phe-pro}}=\frac{0.05}{0.005}$ , T = 298 K , R = 8.314 J/(mol.K) and $E_{a}^{ala-pro}=60kJ/mol$

So, $\frac{0.05}{0.005}=e^{\frac{[E_{a}^{phe-pro}-(60000J/mol)]}{8.314J.mol^{-1}.K^{-1}\times 298K}}$

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So, activation energy of phenylalanine-proline peptide is 66 kJ/mol

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3 years ago

Question 2(Multiple Choice Worth 3 points)

viktelen [127]

Answer:

2.0 x 10⁻³ M/s.

Explanation:

The rate of the reaction is the change of the concentration of the reactants or the products with time.

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To learn more about titration please visit -
brainly.com/question/2728613
#SPJ1

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2 years ago

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4 years ago

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