Why does the mass spectrum of Br2 contain three signals whose heights are almost in the ratio of 1:2:1? What are the origins of
1 answer:
You might be interested in
As we know that work done is defined as product of force and displacement in the direction of applied force
so we can say it is
or we can say
so we will have following options
A)Pushing against a locked door
There is no work done in above case as there will be no displacement in that case so work done is ZERO
B) Carrying a box down a corridor
While we move done and carrying a box then work done by gravity on the box while our work done is negative work.
C) Pulling a trailer up a hill
In above case our work done to pull a box up a hill is positive work as we need to work against gravity
D) Suspending a heavy weight with a strong chain
During suspension there is no displacement so there will be no work done in above case
so correct answer will be
<em>Pulling a trailer up a hill</em>
Answer:
2.84 g's with the remaining 1 g coming from gravity (3.84 g's)
Explanation:
period of oscillation while waiting (T1) = 2.45 s
period of oscillation at liftoff (T2) = 1.25 s
period of a pendulum (T) =2π.
where
- L = length
- a = acceleration
therefore the ration of the periods while on ground and at take off will be
=(2π
) / (2π
)
where
- a1 = acceleration on ground while waiting
- a2 = acceleration during liftoff
=
squaring both sides we have
=
=
assuming that the acceleration on ground a1 = 9.8 m/s^{2}
=
a2 = 9.8 x
substituting the values of T1 and T2 into the above we have
a2 = 9.8 x
a2 = 9.8 x 3.84
take note that 1 g = 9.8 m/s^{2} therefore the above becomes
a2 = 3.84 g's
Hence assuming the rock is still close to the ground during lift off, the acceleration of the rocket would be 2.84 g's with the remaining 1 g coming from gravity.