Select the correct answer What are beats?

How many components can be realized of a vector?

stiv31 [10]

Answer:

<em>two different components</em>

Explanation:

<em>Any two-dimensional vector can be conceived of as having two distinct components. The component of a single vector describes the vector's effect in a specific direction.</em>

3 0

2 years ago

When spiking a volleyball, a player changes the velocity of the ball from 4.2m/s to -24m/s along a certain direction. If the imp

dedylja [7]

Answer:

The mass of the volleyball is 0.32 kg.

Explanation:

Given that,

Initial speed of the ball, u = 4.2 m/s

Final speed of the ball, v = -24 m/s

The impulse delivered to the ball by the player is -9.3 kg-m/s.

To find,

Mass of the volleyball.

Solution,

The change in momentum of the volleyball is equal to the impulse delivered to the ball. It is given by :

$J=m(v-u)$

$m=\dfrac{J}{(v-u)}$

$m=\dfrac{-9.3\ kg-m/s}{(-24-4.2)\ m/s}$

m = 0.32 kg

So, the mass of the volleyball is 0.32 kg.

5 0

3 years ago

A football is thrown horizontally with an initial velocity of(16.6 {\rm m/s} ){\hat x}. Ignoring air resistance, the average acc

Ray Of Light [21]

Answer:

A) 16.6 m/s i -17.2 m/s j B) 23.9 m/s c) 46º below horizontal.

Explanation:

A) Once released, the football is not under the influence of any external force in the horizontal direction, so it continues moving at a constant speed equal to the initial velocity, i.e., 16.6 m/s.

If we choose the horizontal direction to be coincident with the x-axis, and make positive the direction towards the right (assuming that this was the direction along which the football was thrown), we can write the horizontal component of the veelocity vector, as follows:

vₓ = 16.6 m/s i

In the vertical direction, the football, once released, is in free fall, starting from rest.

So, we can find the vertical component of the velocity vector, at a given point in time, applying the definition of acceleration, as follows:

vy = a*t = -g*t = -9.81 m/s²*1.75 s = -17.2 m/s

Assuming that the upward direction is the positive for the y-axis (perpendicular to the chosen x-axis), we can write the vertical component of the velocity vector, at t=1.75 s, as follows:

vy = -17.2 m/s j

So, the velocity vector, in terms of the unit vectors i and j, can be written in this way:

v = 16.6 m/s i -17.2 m/s j

b) The magnitude of this vector can be found applying trigonometry, as the magnitude is the hypotenuse of a triangle with sides equal to vx and vy, as follows:

$v =\sqrt{(16.6m/s)^{2}+ (-17.2m/s)^{2}} = 23.9 m/s$