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Dmitriy789 [7]
3 years ago
7

What is the molecular weight of one mole of H2CO3? g/mole

Chemistry
2 answers:
eimsori [14]3 years ago
6 0
The answer is 62.026 g/mole
sergeinik [125]3 years ago
4 0

Answer:

The answer to the question is 62.026.

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Which statement is true regarding methane and ammonia?
sukhopar [10]
The options for given question are as follow,

1) Methane molecules show hydrogen bonding. 
<span>2) Ammonia molecules show hydrogen bonding. </span>
<span>3) Methane has stronger hydrogen bonding than ammonia. </span>
<span>4) Both the compounds do not show hydrogen bonding. </span>
<span>5) Both the compounds have strong hydrogen bonding.
</span>
Answer:
            Correct answer is Option-2 (Ammonia molecules show hydrogen bonding).

Explanation:
                   Hydrogen bond interactions are formed when a partial positive hydrogen atom attached to most electronegative atom of one molecule interacts with the partial negative most electronegative element of another molecule. So, in Ammonia hydrogen gets partial positive charge as nitrogen is highly electronegative. While the C-H bond in Methane is non-polar and fails to form hydrogen bond interactions.
6 0
3 years ago
Read 2 more answers
With which group would group 18 most likely bond
Mice21 [21]

Answer:

The noble gases (Group 18) are located in the right of the periodic table and were previously referred to as the "inert gases" due to the fact that their filled valence shells (octets) make them extremely nonreactivE

Explanation:

8 0
3 years ago
PLEASE HELP DUE TODAY 55 POINTS
Dvinal [7]

Answer : The final volume of gas will be, 26.3 mL

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.974 atm

P_2 = final pressure of gas = 0.993 atm

V_1 = initial volume of gas = 27.5 mL

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 22.0^oC=273+22.0=295K

T_2 = final temperature of gas = 15.0^oC=273+15.0=288K

Now put all the given values in the above equation, we get:

\frac{0.974 atm\times 27.5 mL}{295K}=\frac{0.993 atm\times V_2}{288K}

V_2=26.3mL

Therefore, the final volume of gas will be, 26.3 mL

3 0
3 years ago
Read 2 more answers
What is the number of moles in 3.0 X 10^24 atoms of Carbon
evablogger [386]

Answer:the number of moles represented by 3.0 x 10^24 atoms of Ag is 0.500mol 0.500 m o l .

Explanation:

4 0
1 year ago
What is the empirical formula of C3H6N2
Evgen [1.6K]

Answer:

The empirical formula of the compound C₃H₆N₂ is C₃H₆N₂

Explanation:

The empirical formula of a compound is the formula of the compound given in the (smallest) whole number ratio of the elements of the compound

The empirical formula of S₂O₂ is SO

The empirical formula of C₃H₆O₃ is CH₂O

The given compound's molecular formula is C₃H₆N₂

The smallest whole number ratio of of the elements of the compound is 3:6:2, therefore, the empirical formula of the compound C₃H₆N₂ is C₃H₆N₂.

4 0
3 years ago
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