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3 years ago

In which block of the periodic table is uranium (U) found?

Chemistry

2 answers:

s344n2d4d5 [400]3 years ago

6 0

Answer:

f block

Explanation:

just did this in class yesterday :)

Alexxx [7]3 years ago

5 0

Answer:

Uranium is in the f block

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Please help me with this I will give out extra points with the brain thing if you help me with this science question 1/7 image b

oksian1 [2.3K]

Answer:

D) The baby will continue to move forward as the car slows and be push into the padded car seat.

Explanation:

Newton's first law states that an object tends to be in a state of rest or motion unless and until an unbalanced external force acts on it. This means a body would continue to be in a state of motion unless external force stops it. A body in the state of rest will remain at rest unless an external force moves it.

An infant car seat is made to face the rear of the car. This is because, in case of a front-end collision, the car would come to a sudden stop but the bodies inside the car are in a state of motion and a sudden halt will cause the body to push in the opposite direction.

Thus, for an infant in the car, it would be a safer measure to place the seat facing the rear o the car because in this case, it would cause the baby to safely collide with the padded seat of the car.

7 0

3 years ago

Read 2 more answers

For the following reaction, 2.45 grams of methane (CH4) are allowed to react with 27.7 grams of carbon tetrachloride . methane (

rosijanka [135]

Answer:

The limiting reactant is CH₄

26.0g of CH₂Cl₂ is the maximum amount that can be formed

4.15g CCl₄ will remain

Explanation:

The reaction of methane, CH₄, with carbon tetrachloride, CCl₄ is:

CH₄ + CCl₄ → 2CH₂Cl₂

To find the maximum mass of dichloromethane that can be determined we need to find moles of methane and carbon tetrachloride:

Moles CH₄:

2.45g * (1mol / 16.04g) = 0.153 moles

Moles CCl₄:

27.7g * (1mol / 153.82g) = 0.180 moles

That means just 0.153 moles of CCl₄ will react until CH₄ is over.

The limiting reactant is CH₄

Assuming the whole 0.153 moles will react, the moles of CH₂Cl₂ will be:

0.153 moles CH₄ * (2 moles CH₂Cl₂ / 1 mole CH₄) = 0.306 moles of CH₂Cl₂

The mass is (Molar mass dichloromethane: 84.93g/mol):

0.306 moles of CH₂Cl₂ * (84.93g / mol) = 26.0g of CH₂Cl₂

The moles of CCl₄ that remain are:

0.180 moles - 0.153 moles = 0.027 moles

In grams:

0.027 moles * (153.82g / mol) = 4.15g CCl₄

3 0

3 years ago

What Celsius temperature, T2, is required to change the volume of the gas sample in Part A (T1 = 23 ∘C , V1= 1.69×103 L ) to a v

andrezito [222]

Answer:

319.15^{o}C[/tex]

Explanation:

When all other variables are constant, we are allowed to use the formula

$\frac{T_{2} }{V_{2} } = \frac{T_{1} }{V_{1} } \\Which can be rewritten as T_{2} = \frac{T_{1} V_{2} }{V_{1} }if you make T2 the subject of the formula. This formula is true only if temperature is in Kelvin not degrees Celsius so T1 must be converted to KelvinNow to calculate T2[tex]T_{2}= \frac{296.15K*3.38.10^{3}L }{1.69.10^{3}L }= 592.3K$ = $319.15^{o} C$