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3 years ago

9

I'll give brainliest

1 answer:

lord [1]3 years ago

4 0

Answer:

I'm thinking its "Your friend had colder winters than you do."

Explanation:

It is not "Your friend has warmer winters than you do." Or "You Have less precipitation than your friend does." I was doing this quiz before that had this question and its not those.

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Which of the following IS NOT a galaxy that the Milky Way is currently "eating"?

Levart [38]

I think it’s the andromeda cause scientists have said that Andromeda might be eating Milky Way.

7 0

1 year ago

Strontium sulfate becomes less soluble in an aqueous solution when sodium sulfator is added because

horsena [70]

Answer:

The addition of sulfate ions shifts equilibrium to the left.

Explanation:

Hello!

In this case, according to the following ionization of strontium sulfate:

$SrSO_3(s)\rightleftharpoons Sr^{2+}+SO_4^{2-}$

It is evidenced that when sodium sulfate is added, sulfate, $SO_4^{2+}$ is actually added in to the solution, which causes the equilibrium to shift leftwards according to the Le Ch athelier's principle. Thus, the answer in this case would be:

The addition of sulfate ions shifts equilibrium to the left.

Best regards!

7 0

2 years ago

Read 2 more answers

303.8 liters volume will be occupied by 217.0 grams of methane gas at STP.

neonofarm [45]

Answer:

False

Explanation:

It will occupy 271.7

4 0

3 years ago

Use the reaction given below to solve the problem that follows: Calculate the mass in grams of aluminum oxide produced by the re

bearhunter [10]

Answer: 28.4 g of aluminum oxide is produced by the reaction of 15.0 g of aluminum metal

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} Al=\frac{15.0g}{27g/mol}=0.556moles$

The balanced chemical equuation is:

$4Al+3O_2\rightarrow 2Al_2O_3$

According to stoichiometry :

4 moles of $Al$ produce == 2 moles of $Al_2O_3$

Thus 0.556 moles of $Al$ will produce= $\frac{2}{4}\times 0.556=0.278moles$ of $Al_2O_3$

Mass of $Al_2O_3=moles\times {\text {Molar mass}}=0.278moles\times 102g/mol=28.4g$

Thus 28.4 g of aluminum oxide is produced by the reaction of 15.0 g of aluminum metal.

7 0

2 years ago

PLEASEEEEEEEEEEEE HELPPPPPPPP I BEGGGGG FOR HELPPPPP

Elza [17]

Answer: There are $21.08\times 10^{23}$ molecules in 63.00 g of $H_2O$

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{63.00g}{18g/mol}=3.5moles$

1 mole of $H_2O$ contains = $6.023\times 10^{23}$ molecules

Thus 3.5 moles of $H_2O$ contains = $\frac{6.023\times 10^{23}}{1}\times 3.5=21.08\times 10^{23}$ molecules.

There are $21.08\times 10^{23}$ molecules in 63.00 g of $H_2O$

3 0

3 years ago