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notsponge [240]
2 years ago
13

2a. Write down the names of the new substances formed when each of the following substance reacts with dilute hydrochloric acid.

Chemistry
2 answers:
Naddika [18.5K]2 years ago
7 0

Answer:

i) Dilute hydrochloric acid will react with Ammonia to form ammonia salt.

ii) dilute hydrochloric acid will react with soduim hydroxide to form sodium chloride and water

iii) dilute hydrochloric acid will react with calcuim carbonate to form Calcium chloride, Carbon dioxide and water.

Explanation:

CHEMICAL EQUATIONS :

I) HCL + NH3 = NH4Cl

ii) HCL+ NaOH = NaCl + H2O

iii) HCL + CaCo = CaCl2 + CO2 + H2O

vampirchik [111]2 years ago
4 0
Sodium hydroxide I think it is right
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Answer:A

Explanation: because i saw the sheet

6 0
2 years ago
How many moles of hydrogen gas will be produced when 12 g of Mg will react completely with excess of an acid according to the fo
lina2011 [118]

Answer:

0.49 mol

Explanation:

Step 1: Write the balanced equation

Mg + 2 HCI ⇒ MgCl₂ + H₂

Step 2: Calculate the moles corresponding to 12 g of Mg

The molar mass of Mg is 24.31 g/mol.

12g \times \frac{1mol}{24.31g} = 0.49mol

Step 3: Calculate the moles of H₂ produced by 0.49 moles of Mg

The molar ratio of Mg to H₂ is 1:1. The moles of H₂ produced are 1/1 × 0.49 mol = 0.49 mol.

7 0
3 years ago
If there are 40 mol of NBr3 and 48 mol of NaOH, what is the excess reactant
Vanyuwa [196]
<h3>Answer:</h3>

              Excess Reagent =  NBr₃

<h3>Solution:</h3>

The Balance Chemical Equation for the reaction of NBr₃ and NaOH is as follow,

                       2 NBr₃ + 3 NaOH   →   N₂ + 3 NaBr + 3 HBrO

Calculating the Limiting Reagent,

According to Balance equation,

               2 moles NBr₃ reacts with  =  3 moles of NaOH

So,

           40 moles of NBr₃ will react with  =  X moles of NaOH

Solving for X,

                       X  =  (40 mol × 3 mol) ÷ 2 mol

                       X  =  60 mol of NaOH

It means 40 moles of NBr₃ requires 60 moles of NaOH, while we are provided with 48 moles of NaOH which is Limited. Therefore, NaOH is the limiting reagent and will control the yield of products. And NBr₃ is in excess as some of it is left due to complete consumption of NaOH.

6 0
3 years ago
Select the correct answer. Elements Electronegativity aluminum (Al) 1.61 calcium (Ca) 1 carbon (C) 2.55 chlorine (Cl) 3.16 fluor
marishachu [46]

Answer: Fe - O


Explanation:


1) Start by showing the chart information in a more understandable way:


Elements ---------- Electronegativity


aluminum (Al) ----- 1.61


calcium (Ca) ------- 1


carbon (C) ---------- 2.55


chlorine (Cl) -------- 3.16


fluorine (F) --------- 4


hydrogen (H) ------ 2.2


iron (Fe) ------------- 1.83


nitrogen (N) --------- 3.04


oxygen (O) ----------- 3.44


phosphorus (P) ----- 2.19


potassium (K) -------- 0.82


silicon (Si) ------------- 1.9


sulfur (S) --------------- 2.58


2) Find the electronegativity differences for the atoms in each compound:


i) Ca – Cl: 3.16 - 1 = 2.16


ii) Fe – O: 3.44 - 1.83 = 1.61


iii) H – S: 2.58 - 2.2 = 0.38


iii= F – F = 4 - 4 = 0


3) Analysis


i) The higher the electronegativity difference between two non-metal elements, the the more the polar the covalent bond. Therefore, the bond H - S is the most polar among the non-metal - non-metal bonds listed. But 0.38 is a small difference, so this is not very polar.


ii) For metal - non-metal bonds, when the difference in electronegativities is too high (close to or greater than 2.0) the ionic character is dominant, and so you cannot classify the bond as polar but as ionic. Therefore, Ca - Cl with 2.16 electronegativity difference is a ionic bond.


iii) The bond in Fe – O has electronegativty difference of 1.61, so it is yet covalent, and highly polar.


Read more on Brainly.com - brainly.com/question/1309389#readmore


<h3>~*"AUBA14"*~</h3>
8 0
3 years ago
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natima [27]
Yes, o-toluic acid is soluble in ether as ether is slightly polar and it is soluble in NaOH because it is likely to form soluble compounds with it.

Naphthalene is insoluble in NaOH.
8 0
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