Question

Use the confidence level and sample data to find the margin of error E. Round your answer to the same number of decimal places as the sample mean unless otherwise noted.
Weights of eggs: 95% confidence; n=53, /x =1.34 oz, standard deviation = 0.58 oz



A.) (0 pts) 0.13 oz


B.) (0 pts) 0.02 oz


C.) (1 pts) 0.16 oz


D.) (0 pts) 0.36 oz

Answer 1

Answer: option c

Step-by-step explanation:

margin of error = critical value × s/√n

Where s = sample standard deviation = 0.58, n = 53

The critical value = 1.96 ( this is the critical value for a two test test corresponding to a level of significance of 5%)

By substituting the parameters, we have that

Margin of error = 1.96×0.58/√53

Margin of error = 1.96 × 0.0796

Margin of error = 0.156 ~ 0.16