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Fantom [35]
3 years ago
5

Why is energy important to motion?

Physics
2 answers:
Bumek [7]3 years ago
8 0
Energy is the force that creates motion
Inessa [10]3 years ago
8 0
Because motion only occur or cease when there is a force, and force is created by energy.
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What is 25 degrees Celsius equal to in Fahrenheit? I need to know how to do it to, so give me a formula, and it would help if yo
andreev551 [17]
C= 5/9*(F - 32) so F=C*9/5 + 32

F= 25*9/5 +32 = 77 Fahrenheit
5 0
3 years ago
How do animals get the nitrogen they need<br>​
Alenkinab [10]

Answer:

Animals get the nitrogen they need by eating plants or other animals that contain nitrogen.

Explanation:

4 0
3 years ago
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Andru [333]

Answer:

LLOLL

Explanation:

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3 years ago
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The wheel of a car has a radius of 20.0 cm. It initially rotates at 120 rpm. In the next minute it makes 90.0 revolutions. (a) W
just olya [345]

Answer:

Explanation:

Given that,

Radius of the wheel, r = 20 cm = 0.2 m

Initial speed of the wheel, \omega_i=120\ rpm=753.98\ rad/s

Displacement, \theta=90\ rev=565.48\ rad

To find,

The angular acceleration and the distance covered by the car.

Solution,

Let \alpha is the angular acceleration of the car. Using equation of rotational kinematics as :

\theta=\omega_i t+\dfrac{1}{2}\alpha t^2

565.48=753.98\times 60+\dfrac{1}{2}\alpha (60)^2

\alpha =-24.81\ rad/s^2

Let t is the time taken by the car before coming to rest.

t=\dfrac{\omega_f-\omega_i}{\alpha }

t=\dfrac{0-753.98}{-24.81}

t = 30.39 seconds

Let v is the linear velocity of the car. So,

v=r\times \omega_i

v=0.2\times 753.98

v = 150.79 m/s

Let d is the distance covered by the car. It can be calculated as :

d=v\times t

d=150.79\ m/s\times 30.39\ s

d = 4582.5 meters

or

d = 4.58 km

5 0
3 years ago
Point charges q1 and q2 are separated by a distance of 60 cm along a horizontal axis.
amm1812

Answer:

38 cm from q1(right)

Explanation:

Given, q1 = 3q2 , r = 60cm = 0.6 m

Let that point be situated at a distance of 'x' m from q1.

Electric field must be same from both sides to be in equilibrium(where EF is 0).

=> k q1/x² = k q2/(0.6 - x)²

=> q1(0.6 - x)² = q2(x)²

=> 3q2(0.6 - x)² = q2(x)²

=> 3(0.6 - x)² = x²

=> √3(0.6 - x) = ± x

=> 0.6√3 = x(1 + √3)

=> 1.03/2.73 = x

≈ 0.38 m = 38 cm = x

8 0
3 years ago
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