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3 years ago

Determine the acceleration of a pendulum bob as it passes through an angle of 15 degrees to the right of the equilibrium point.

Physics

1 answer:

BigorU [14]3 years ago

7 0

Answer:

Explanation:

Since energy is conserved:

+mgh

⇒u

+2gh

⇒(3)

+2(9.8)(0.5−0.5cos60)

⇒v=2m/s

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2 years ago

Brad has three beakers of water. Each beaker contains 500 mL of water. The temperature of the water in the first beaker is 40°C.

dexar [7]

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3 years ago

A body is at equilibrium under the action of three forces. One force is 10N acting due east and one is 5N in the direction 60° n

olchik [2.2K]

Answer:

If the body is in equilibrium the two forces add up and the third is the opposite of the resultant.

F(1x)=F(1)=10 N

F(2x)=F(2)cos60=5•0.5=2.5 N

F(2y) =F(2)sin60 = 5•0.866= 4.33 N

F(3x) =- F(x)=- (10+2.5 )= -12.5 N

F(3y) =- F(2y)= - 4.33 N

F(3) = sqrt{ F(3x)²+F(3y)²} =13.23 N

tan φ = F(3y)/F(3x) =4.33/12.5=0.364

φ = 19.1⁰ (south-west)

Explanation:

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3 years ago

A girl and her bicycle have a total mads of 42 kg. At the top of the hill her speed is 4 m/s. The hill is 14.3m high and 112m lo

frosja888 [35]

Answer:

13.78 m/s

Explanation:

Given that:

The mass of the girl & her bicycle = 42 kg

The speed at the top of the hilll= 4 m/s

The height of the hill = 14.3 m

The length of the hill (distance) = 112 m

The frictional force = 20 N

To find the speed at the bottom of the hill; we need to carry out the following processes.

The workdone by gravity = mass × acceleration due to gravity × Δh

= 42 × 9.8 × ( 14.3 - 0 )

= 5885.88 joules

The workdone by the friction = Force × distance = - 20 × 112 (since she is riding down the hill)

The workdone by the friction = -2240 Joules

The initial Kinetic friction = 1/2 mv²

= 1/2 × 42 × 4²

= 336 Joules

The final kinetic energy = Initial Kinetic energy + total work

The final kinetic energy = (336 + 5885.88 - 2240) Joules

The final kinetic energy = 3981.88 Joules

Using the final kinetic energy = 1/2 mv²

3981.88 = 1/2 × 42 × v²

3981.88 = 21 v²

v² = 3981.88/21

v² =189.61

v = $\sqrt{189.61}$

v = 13.78 m/s

Therefore, the speed at the bottom = 13.78 m/s

4 0

3 years ago