Answer: 2.068*m
Explanation: According to work energy-theorem , the workdone in accelerating the electron equals the energy it would give off in terms of light.
workdone= qV
energy = hc/λ
q=magnitude of an electronic charge= 1.602*
h= planck constant = 6.626*
c= speed of light =2.998*
v= potential difference= 6*
λ= wavelength=unknown
by making λ subject of formulae we have that
λ=
λ = 6.626* * 2.998* / 1.602* * 6*
λ =
by doing the necessary calculations, we have that
λ = 2.068*m
Answer:
2.5 m/s
Explanation:
Mechanical energy is the sum of the potential and kinetic energy.
E = PE + KE
E = mgh + ½mv²
172.1 J = (7.26 kg) (9.8 m/s²) (2.1 m) + ½ (7.26 kg) v²
v = 2.5 m/s
Answer:
The necessary separation between the two parallel plates is 0.104 mm
Explanation:
Given;
length of each side of the square plate, L = 6.5 cm = 0.065 m
charge on each plate, Q = 12.5 nC
potential difference across the plates, V = 34.8 V
Potential difference across parallel plates is given as;
Where;
d is the separation or distance between the two parallel plates;
Therefore, the necessary separation between the two parallel plates is 0.104 mm
It is A or D but I believe A