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4 years ago

Which statement is true of an object in equilibrium

2 answers:

8 0

If I remember correctly, it is a state an object is in when no force is acting on it or when there is equal amount of force in each direction is being applied to it. Basically, either the object is motionless or is traveling at a constant velocity, there is no acceleration.

Olin [163]4 years ago

6 0

The rate of the forward reaction is equal to the rate of the reverse reaction.

Equilibrium is reached when the rates of the forward and reverse reactions are the same.

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The solid right-circular cylinder of mass 500 kg is set into torque-free motion with its symmetry axis initially aligned with th

aivan3 [116]

Answer:

30.95°

Explanation:

We need to define the moment of inertia of cylinder but in terms of mass, that equation say,

$A=\frac{1}{12}m(3r^2+l^2)$

Replacing the values we have,

$A=\frac{1}{12}(500)(3(0.5)^2+(2)^2)$ $A=197.9kg.m^2$

At the same time we can calculate the mass moment of intertia of cylinder but in an axial way, that is,

$c=\frac{1}{2}mr^2$

$c=\frac{1}{2}(500)(0.5)^2$

$c=62.5kg.m^2$

Finally we need to find the required angle between the fixed line a-a (I attached an image )

$\Phi = 2tan^{-1}\sqrt{\frac{(\frac{A}{cos\gamma})^2-A^2}{c^2}}$

Replacing the values that we have,

$\Phi = 2tan^{-1}\sqrt{\frac{(\frac{197.9}{cos5\°})^2-197.9^2}{62.5^2}}$

$\Phi = 2tan^{-1}(\sqrt{0.076634})$

$\Phi = 2tan^{-1}(0.2768)$

$\Phi = 2(15.47)$

$\Phi = 30.95\°$

4 0

4 years ago

A force of 73.8 newtons is applied to travel bag at an angle 39.0° with the horizontal. What are the horizontal and vertical com

Semenov [28]

The horizontal component of the force is the product of the cosine of the angle and the magnitude of the force, Fx = (73.8 N)(cos 39) = 57.35 N. The vertical component of this force is the product of the sine of the angle and the force, Fy = (73.8 N)(sin 39) = 46.44 N.

5 0

3 years ago

When populations of two species work together to obtain resources, they are

valina [46]

<span>cooperation. i think that is it

</span>

7 0

3 years ago

Read 2 more answers

Use the ratio version of Kepler’s third law and the orbital information of Mars to determine Earth’s distance from the Sun. Mars

zhuklara [117]

Kepler's third law is used to determine the relationship between the orbital period of a planet and the radius of the planet.

The distance of the earth from the sun is $1.50 \times 10^{11}\;\rm m$ .

<h3>What is Kepler's third law?</h3>

Kepler's Third Law states that the square of the orbital period of a planet is directly proportional to the cube of the radius of their orbits. It means that the period for a planet to orbit the Sun increases rapidly with the radius of its orbit.

$T^2 \propto R^3$

Given that Mars’s orbital period T is 687 days, and Mars’s distance from the Sun R is 2.279 × 10^11 m.

By using Kepler's third law, this can be written as,

$T^2 \propto R^3$

$T^2 = kR^3$

Substituting the values, we get the value of constant k for mars.

$687^2 = k\times (2.279 \times 10^{11})^3$

$k = 3.92 \times 10^{-29}$

The value of constant k is the same for Earth as well, also we know that the orbital period for Earth is 365 days. So the R is calculated as given below.

$365^3 = 3.92\times 10^{-29} R^3$