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vlada-n [284]
2 years ago
5

What term is used to describe all of the wavelengths of light waves?

Physics
1 answer:
Aneli [31]2 years ago
3 0

Answer:

B.electromagnetic spectrum

Explanation:

Electromagnetic spectrum is used to  describe all of the wavelengths of light waves.Generally wavelength of the wave is denoted by λ.

Wavelength is the distance between two consecutive crest .Wavelength of the red color is minimum and wavelength of the violet color is maximum in the light  spectrum.

So the answer is B.

Electromagnetic spectrum

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A resistor is connected in series with an AC source that provides a sinusoidal voltage of v of t is equal to V times cosine of b
nekit [7.7K]
<h2>Answer:</h2>

In circuits, the average power is defined as the average of the instantaneous power  over one period. The instantaneous power can be found as:

p(t)=v(t)i(t)

So the average power is:

P=\frac{1}{T}\intop_{0}^{T}p(t)dt

But:

v(t)=v_{m}cos(\omega t) \\ \\ i(t)=i_{m}cos(\omega t)

So:

P=\frac{1}{T}\intop_{0}^{T}v_{m}cos(\omega t)i_{m}cos(\omega t)dt \\ \\ P=\frac{v_{m}i_{m}}{T}\intop_{0}^{T}cos^{2}(\omega t)dt \\ \\ But: cos^{2}(\omega t)=\frac{1+cos(2\omega t)}{2}

P=\frac{v_{m}i_{m}}{T}\intop_{0}^{T}(\frac{1+cos(2\omega t)}{2} )dt \\\\P=\frac{v_{m}i_{m}}{T}\intop_{0}^{T}[\frac{1}{2}+\frac{cos(2\omega t)}{2}]dt \\\\P=\frac{v_{m}i_{m}}{T}[\frac{1}{2}(t)\right|_0^T +\frac{sin(2\omega t)}{4\omega} \right|_0^T] \\ \\ P=\frac{v_{m}i_{m}}{2T}[(t)\right|_0^T +\frac{sin(2\omega t)}{2\omega} \right|_0^T] \\ \\ P=\frac{v_{m}i_{m}}{2}

In terms of RMS values:

V_{RMS}=V=\frac{v_{m}}{\sqrt{2}} \\ \\ I_{RMS}=I=\frac{i_{m}}{\sqrt{2}} \\ \\ Then: \\ \\ P=VI

7 0
2 years ago
A group of astrologers have written a book about how to use the stars to help you choose the right friends. This could be consid
Mrac [35]

Answer:b- Psuedoscience

Explanation:

It is a pseudoscience because it involves beliefs and practices which is mistakenly regarded as being based on scientific grounds.

No solid evidence is there which can prove that astrology is authentic and true that's why it is a Psuedo science

8 0
2 years ago
An object is acted upon by a force of 22 newtons to the right and a force of 13 newtons to the left. What is the magnitude and d
Harman [31]

The magnitude and direction of the net force is 9 newtons to the right ⇒ answer A

Explanation:

The net force is the vector sum of all the forces that act upon an object

If two forces are horizontal where,

  • F_{1} > F_{2}
  • They are in opposite direction
  • Net force F = F_{1} - F_{2} in the direction of F_{1}

An object is acted upon by a force of 22 newtons to the right

and a force of 13 newtons to the left

We need to find the magnitude and direction of the net force

→ F_{1} = 22 newtons to the right

→ F_{2} = 13 newtons to the left

F_{1} > F_{2} and they are in opposite direction

Substitute these values in the rule of the net force above

→ Net force F = 22 - 13 = 9

→ The direction of the net force is the same direction of the larger

   force, the direction of the larger force is to the right

→ Net force is 9 newtons to the right

The magnitude and direction of the net force is 9 newtons to the right

Learn more:

You can learn more about the net force in brainly.com/question/4033012

#LearnwithBrainly

8 0
3 years ago
A magnetic field is perpendicular to the plane of a flat coil. Since the magnitude of the field is increasing, an emf will be in
Blababa [14]

Answer:

D) Reduce the time interval during which the magnitude of the field increases.

6 0
2 years ago
If two measurements are very close to each other, then they are ____.
dimaraw [331]
I'd say b, precise, here.
If there's an error somewhere in the experiment or project, then it is consistently .... wrong. So, just 'cos you measure something precisely, it doesn't mean that you've measured it accurately. Maybe an example would be a measurement of length. If you used a metal ruler at zero degrees C, you can measure to say half a millimetre. A series of measurements of the same object would give very similar readings. But, if you used same metal ruler at, say 100 celsius (implausible) then you'd probably get a different set of readings. 'cos of the expansion of the metal ruler.
4 0
3 years ago
Read 2 more answers
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