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Vera_Pavlovna [14]
3 years ago
13

Free 25 points cause why the hell not

Physics
2 answers:
hodyreva [135]3 years ago
4 0

Answer:

I love nice people. Doing anything interesting for Thanksgiving?

Stolb23 [73]3 years ago
3 0

Answer:

Ty

Explanation:

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If the current flowing through a circuit of constant resistance is doubled, the power dissipated by that circuit will
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Assuming that the voltage is constant, and the resistance was doubled, since I=V/R, the current through the circuit will be halved. As P=IV, with the same voltage and halved current, the power dissipated by the circuit will be halved
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The answer is A.

Explanation:

The graph would show the unit rate otherwise known as a ratio

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3 years ago
How high off the ground must you be if you mass is 75 kg and you have 11,025 J of energy stored inside?
pashok25 [27]

Answer:

15 m

Explanation:

Given,

Mass ( m ) = 75 kg

Potential energy ( P.E ) = 11,025 J

To find : Hight ( h )

Formula : -

P.E = mgh

[ Note : The value of g = 9.8 m/s² ]

h = P.E / mg

  = 11,025 / ( 75 x 9.8 )

  = 11,025 / 735

h = 15 m

Hence,

15 m is the high off the ground must you be if you mass is 75 kg and you have 11,025 J of energy stored inside.

3 0
2 years ago
Three objects lie in the x, y plane. Each rotates about the z axis with an angular speed of 5.58 rad/s. The mass m of each objec
QveST [7]

Answer:

a) V1=11.05m/s    V2=92.07m/s     V3=17.24m/s

b) KE = 16238.26J

Explanation:

For tangential speeds:

V1 = \omega*R1=5.58*1.98=11.05m/s

V2 = \omega*R2=5.58*16.5=92.07m/s

V3 = \omega*R3=5.58*3.09=17.24m/s

For the kinetic energy, it can be calculated as:

KE=1/2*\omega^2*(I1+I2+I3)

Where:

I1 = m1*R1^2=5.46*1.98^2=21.4kg.m^2

I2 = m2*R2^2=3.64*16.5^2=990.99kg.m^2

I3 = m3*R3^2=3.21*3.09^2=30.65kg.m^2

So,

KE=1/2*5.58^2*(21.4+990.99+30.65)

KE=16238.26J

4 0
3 years ago
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