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2 answers:
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Answer:
velocity of truck = 7.32 m/s
velocity of truck = 23.32 m/s
Explanation:
mass of truck, M = 1810 kg
initial velocity of truck, U = 16 m/s
mass of car, m = 673 kg
initial velocity of car, u = 0 m/s
Let the final speed of the car is v and the final speed of truck is V.
Use conservation of momentum
Momentum before collision = Momentum after collision
M x U + m x 0 = M x V + m x v
1810 x 16 + 0 = 1810 V + 673 v
28960 = 1810 V + 673 v .... (1)
As the collision is elastic, so the coefficient of restitution is 1.
By using the formula
where, u1 be the initial velocity of truck, u2 be the initial velocity of the car, v1 be the final velocity of truck and v2 be the final velocity of car.
V - v = - U
V - v = - 16
v - V = 16
v = 16 + V
Substitute in equation (1), we get
28960 = 1810 V + 673 (16 + V)
28960 = 1810 V + 10768 + 673 V
18192 = 2483 V
V = 7.32 m/s
v = 16 + 7.32 = 23.32 m/s
Thus, the velocity of truck after collision is 7.32 m/s and the velocity of car after collision is 23.32 m/s.