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mr Goodwill [35]
3 years ago
15

3. Ifthe50.00mLsamplefromproblem2abovewastitratedwitha0.00505MEDTA, what volume (in milliliters) of EDTA solution would be neede

d to reach the endpoint? 4. Agroupofstudentstitrateacalciumcarbonatestandardsolutionrepeatedlyinsix experimental trials. Based on the six trials, the group determines that the average concentration of the standard is 70.5 ppm with a standard deviation of 0.8 ppm. Using the equation for the Student’s t confidence interval found on page 41 of your lab manual and the t-value for a 95% confidence interval (refer to table on page 41), calculate the confidence interval for which there is a 95% chance of finding the “true value” of the standard solution’s concentration based on the data. Put your answer in the format # lower limit < “true value” < # upper limit.
Chemistry
1 answer:
LUCKY_DIMON [66]3 years ago
8 0
What was problem 2? Not sure which question you want answered here.
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I need help fast...........
guapka [62]

Answer:

I think its might be 1 because the ionic numbers for CA is +2 and for P its +3

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2 years ago
6Most types of heather grow better in acidic soil.
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3 0
2 years ago
Identify the true statement(s). There may be one answer or more than one answer.FADH2 is a reducing agent. FADH2 is an oxidizing
adell [148]

Answer:

FADH2 is a reducing agent.

FAD is an oxidizing agent.

Explanation:

The full form of FAD is flavin adenine dinucleotide. It is mainly a redox-active coenzyme which is associated with the different proteins and is involved with the enzymatic reactions in the metabolism.

FAD is obtained by donating or accepting electrons.

In the citric acid cycle,

succinate + FAD → fumarate + $FADH_2$

Thus we see that FAD is an oxidizing agent while $FADH_2$ is a reducing agent.      

8 0
3 years ago
Which element, Sulfur or Chlorine, would have the higher first ionization energy?
Lyrx [107]

Answer:

Chlorine

Explanation:

7 0
3 years ago
Read 2 more answers
How many Moles of NAOH are present in 2.50L of 0.300 M NaOH?
maw [93]
<h3>Answer:</h3>

0.75 moles NaOH

<h3>Explanation:</h3>

We are given;

Volume of NaOH solution = 2.5 Liters

Molarity of NaOH = 0.300 M

We are required to calculate the moles of NaOH

We need to establish the relationship between moles, molarity and volume of a solution.

That would be;

Concentration/molarity = Moles ÷ Volume

Therefore;

Moles = Concentration × Volume

Thus;

Moles of NaOH = 0.300 moles × 2.50 L

                         = 0.75 moles

Therefore, the number of moles of NaOH is 0.75 moles

8 0
3 years ago
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