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mr Goodwill [35]
4 years ago
15

3. Ifthe50.00mLsamplefromproblem2abovewastitratedwitha0.00505MEDTA, what volume (in milliliters) of EDTA solution would be neede

d to reach the endpoint? 4. Agroupofstudentstitrateacalciumcarbonatestandardsolutionrepeatedlyinsix experimental trials. Based on the six trials, the group determines that the average concentration of the standard is 70.5 ppm with a standard deviation of 0.8 ppm. Using the equation for the Student’s t confidence interval found on page 41 of your lab manual and the t-value for a 95% confidence interval (refer to table on page 41), calculate the confidence interval for which there is a 95% chance of finding the “true value” of the standard solution’s concentration based on the data. Put your answer in the format # lower limit < “true value” < # upper limit.
Chemistry
1 answer:
LUCKY_DIMON [66]4 years ago
8 0
What was problem 2? Not sure which question you want answered here.
You might be interested in
Please help me with this question
yKpoI14uk [10]

The mass of oxygen is 236.4 g.

Explanation:

To find the mass of oxygen in 325 g of carbon dioxide (CO₂) we follow the next algorithm.

First we calculate the molar weight of carbon dioxide:

molar weight of CO₂ = molar weight of carbon × 1 + molar weight of oxygen × 2

molar weight of CO₂ = 12 × 1 + 16 × 2 = 44 g/mole

Now we devise the following reasoning:

if in        44 g of CO₂ there are 32 g of oxygen

then in  325 g of CO₂ there are X g of oxygen

X = (32 × 325) / 44 = 236.4 g oxygen

Learn more about:

molar weight

brainly.com/question/9883301

#learnwithBrainly

6 0
3 years ago
To perform a certain type of blood analysis, lab technicians must perform two procedures. The first procedure requires either on
kirza4 [7]

Answer: There are 6 different outcomes.

Explanation:

There are two options for procedure one (one or two steps) and three options for procedure two (one, two or three steps). If we multiply those options , the result is the total number of outcomes for the analysis.

2 x 3 = 6

These being

- One step on procedure one and one step on procedure two

- One step on procedure one and two steps on procedure two

- One step on procedure one and three steps on procedure two

- Two steps on procedure one and one step on procedure two

- Two steps on procedure one and two steps on procedure two

- Two steps on procedure one and two steps on procedure two

7 0
3 years ago
Balance each of the following examples of heterogeneous equilibria and write each Kc expression. Then calculate the value of Kc
marysya [2.9K]

Explanation:

1) 2 Al(s) + 2 NaOH(aq) + 6 H_2O(l) \longleftrightarrow 2 Na[Al(OH)_4](aq) + 7 H_2(g)

Kc=\frac{[Na[Al(OH)_4]]^2*[H_2]^7}{[NaOH]^2}

The Kc for the reverse reaction is the inverse of the Kc of the reaction:

Kc_{reverse}=\frac{1}{Kc}=\frac{1}{11}=0.091

2) H_2O(l) + SO_3(g) \longleftrightarrow H_2SO_4 (aq)

Kc=\frac{[H_2SO_4]}{[SO_3]^2}

The Kc for the reverse reaction is the inverse of the Kc of the reaction:

Kc_{reverse}=\frac{1}{Kc}=\frac{1}{0.0123}=81.3

3)  P_4(s) + 3 O_2(g) \longleftrightarrow P_4O_6(s)

Kc=\frac{1}{[O_2]^3}

The Kc for the reverse reaction is the inverse of the Kc of the reaction:

Kc_{reverse}=\frac{1}{Kc}=\frac{1}{1.56}=0.641

5 0
4 years ago
What do you know for sure after one test? Two tests? Three tests?
Zanzabum
That you have to do better
8 0
3 years ago
The atomic mass of sulfur is 32.1 amu, and the atomic mass of oxygen is 16.0 amu. To the nearest tenth of a percent, what is the
Zielflug [23.3K]

Answer:

\%\ Composition\ of\ sulfur=40.1\ \%

Explanation:

Percent composition is percentage by the mass of element present in the compound.

Given , Mass of sulfur= 32.1 amu

Mass of oxygen = 16.0 amu

Mass of sulfur trioxide SO_3 = 32.1 amu + 3*16.0 amu = 80.1 amu

\%\ Composition\ of\ sulfur=\frac{Mass_{sulfur}}{Mass_{SO_3}}\times 100

\%\ Composition\ of\ sulfur=\frac{32.1\ amu}{80.1\ amu}\times 100=40.1\ \%

6 0
3 years ago
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