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3 years ago

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most planets have --- but none has a --- like earth does. A. a biosphere; hydrosphere., B. an atmosphere; cryosphere., C. an atm

osphere; hydrosphere., D. a hydrosphere; lithosphere

2 answers:

liraira [26]3 years ago

5 0

C. is the answer. i know because i had this question not that long ago.

Dahasolnce [82]3 years ago

4 0

Hi!

~Reply :
C" İt will be :)

Good Luck!

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Hydrogen gas is collected over water in an inverted buret. If the atmospheric pressure is 745 mm Hg, the vapor pressure of water

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Answer:

$P_{H_2}=727mmHg$

Explanation:

Hello there!

In this case, according to the given data, it is possible to infer that the gas mixture lies on the 15.0 cm-high column of water, so that the total pressure or atmospheric pressure is given by:

$P_{atm}=P_{water}+P_{H_2}$

Thus, since the atmospheric pressure is 745 mmHg and the vapor pressure of water is 18 mmHg, the pressure of hydrogen turns out to be:

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3 years ago

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lorasvet [3.4K]

Explanation:

The reaction equation will be as follows.

$CO_{2}(aq) + H_{2}O \rightleftharpoons H^{+}(aq) + HCO^{-}_{3}(aq)$

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$CO_{2}(aq) = K_{CO_{2}} \times P_{CO_{2}}$

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Hence, $[CO_{2}]$ will be calculated as follows.

$[CO_{2}]$ = $K_{CO_{2}} \times P_{CO_{2}}$

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= $0.0608 \times 10^{-4}$

or, = $0.608 \times 10^{-5}$

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As, $K_{a} = \frac{[H^{+}]^{2}}{[CO_{2}]}$

$4.46 \times 10^{-7} = \frac{[H^{+}]^{2}}{0.608 \times 10^{-5}}$

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$[H^{+}]$ = $1.64 \times 10^{-6}$

Since, we know that pH = $-log [H^{+}]$

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3 years ago

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Answer:

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Drag each tile to the correct box.

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