<span>Hydrogen bonds are
approximately 5% of the bond strength of covalent bonds, for example (C-C or C-H
bonds).
Hydrogen bonds strength in water is approximately 20
kJ/mol, strenght of carbon-carbon bond is approximately 350 kJ/mol
and strengh of carbon-hydrogen bond is approximately 340 kJ/mol.
20 kJ/350 kJ = 0,057 = 5,7 %.</span>
Answer:
The final balanced equation is :

Explanation:

Balancing in acidic medium:
First we will determine the oxidation and reduction reaction from the givne reaction :
Oxidation:

Balance the charge by adding 2 electrons on product side:
....[1]
Reduction :

Balance O by adding water on required side:

Now, balance H by adding
on the required side:

At last balance the charge by adding electrons on the side where positive charge is more:
..[2]
Adding [1] and [2]:

The final balanced equation is :

Answer:
1: due to difference in reactivity and melting point
2 during the reaction both combine with oxygen in this case magnesium remain solid but some potassium vaporise
Explanation:
As the given data is as follows.
Height, H = 150 feet
Heat gain = 30,000 BTU/hr, and Heat loss = 25000 BTU/hr
m = mass of water heated = 700 gallons = 5810 lbs
is the heat capacity of water = 1 BTU/lb
(given)
= temperature difference = 
Heat energy required to heat 700 gal can be calculated as follows:
Heat Required = 
Thus, water rises till
.
Counting atoms in a compound can be done by taking one element at a time and multiplying the subscript of the element and the number of molecules of the compounds. For example, H2O, there are two atoms of H adn 1 atom of oxygen.