This question can be solved with the help of the equations of motion.
A) The Frisbee will remain in the air for "5.87 s".
B) The frisbee will go "29.4 m" down the range.
A)
To calculate the time, the frisbee will remain in the air, we will use the second <em><u>equation of motion</u></em>, for the vertical motion.
where,
h = height = 169.2 m
vi = initial velocity's vertical component = 0 m/s
g = acceleration due to gravity = 9.81 m/s²
t = time = ?
Therefore,
<u>t = 5.87 s</u>
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B)
Now, we will calculate the horizontal range by applying the equation for constant motion. Because the velocity in the horizontal direction will remain constant due to no air resistance
s = vt
where,
s = horizontal range = ?
v= initial velocity's horizontal component = 5 m/s
t = time = 5.87 s
Therefore,
s = (5 m/s)(5.87 s)
<u>s = 29.4 m</u>
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Learn more about <em><u>equations of motion</u></em> here:
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Let us first find out the radioactive constant of Phosphorus 32.
Radioactive constant, λ =
Here, is half life of phosphorus 32 = 14.3 days
λ =
The amount of 4 mg of phosphorus remain after 71.5 days can be found using the formula,
m=m₀e⁻(λt)
=
=
=
=
=
= 0.125 mg
The mass of 4 mg of phosphorus 32 remains after 71.5 days will be 0.125 mg.
I don't see an image. Sorry I couldn't help you
I think it is 12 because i
Answer:
The moon is farther away from the earths gravitational pull :)
Explanation: