Answer:
The resulting magnetic force on the wire is -1.2kN
Explanation:
The magnetic force on a current carrying wire of length 'L' with current 'I' in a magnetic field B is
F = I (L*B)
Finding (L * B) , where L = (2, 0, 0)m , B = (30, -40, 0)
L x B = ![\left[\begin{array}{ccc}i&j&k\\2&0&0\\30&-40&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C2%260%260%5C%5C30%26-40%260%5Cend%7Barray%7D%5Cright%5D)
= (0, 0, -80)
we can now solve
F = I (L x B) = I (-80)
F = -1200 kmN
F = -1200 kN * 10⁻³
F = -1.2kN
Is the physical phenomena arising from the force caused by magnet objects that produce fields that attract or repel other objects while magnetic field is a region around the magnetic material or a moving electric charge within the force of magnetism acts
The horizontal displacement of a projectile launched at an angle
3 is 3.81 meters
4 is 0.47 liters
5 is 4 cm
6 is 23 mm
7 is 53 m
8 is 1800 mg
9 is 31.07 mi
Hope I’m helping ya
