When iodine heptafluoride reacts rapidly with water to give a mixture of periodic acid and hydrofluoric acid. Reaction equation for the same is as follows.

$IF_{7} + 6H_{2}O \rightarrow H_{5}IO_{6} + 7HF$

As it is given that there are $3.72 \times 10^{-2}$ moles of iodine heptafluoride are present. Molar mass of $IF_{7}$ is 259.9 g/mol. Molar mass of $HIO_{4}$ is 227.94 g/mol and molar mass of HF is 20.01 g/mol.

Now, according to the reaction equation $3.72 \times 10^{-2}$ M $IF_{7}$ gives $3.72 \times 10^{-2}$ M $H_{5}IO_{6}$ .

Also, the volume is given as 795 ml or 0.795 L (as 1 mL = 0.001 L).

Hence, calculate the concentration of $H_{5}IO_{6}$ into the solution as follows.

Concentration = $\frac{\text{no. of moles}}{volume}$

= $\frac{3.72 \times 10^{-2}}{0.795 L}$

= $4.7 \times 10^{-2}$ mol/L

or, = 0.047 M

Now, as 1 mol of $IF_{7}$ produces 7 mol HF. So, $7 \times 3.72 \times 10^{-2} = 26.04 \times 10^{-2}$ M HF.

Therefore, concentration of HF will be calculated as follows.

Concentration of HF = $\frac{0.2604}{0.795}$

= 0.33 M

Thus, we can conclude that concentration of periodic acid is 0.047 M and concentration of hydrofluoric acid is 0.33 M.

8 0

3 years ago

The mass of an iron(II) sulfate crystal is 8.36 g.How many moles of FeSO4 are in the crystal?

Yuki888 [10]

The number of moles present in the FeSO4 are 0.055 mol.

Explanation:

The mass of a substance containing the same number atoms in 12.0 g of 12C is known as mole. One mole of any substance is equal to 6.023 x 10^23. The moles of a substance can be determined by using the formula,

Number of moles = mass in grams / molecular mass

Given,

mass = 8.36 g,

molecular mass of FeSO4 = 151.908 g / mol

number of moles = 8.36 / 151.908

= 0.055 mol.

5 0

4 years ago