Answer:
The ratio 35Cl/37Cl = 3/1
Explanation:
<u>Step 1:</u> Data given
Chlorine has 2 isotopes:
- mass = 35 g/mol
- mass = 37 g/mol
Average molar mass of chlorine = 35.5 grams
<u>Step 2: </u>Calculate the % of isotopes
35x + 37y = 35.5
x+y = 1 or x = 1-y
35(1-y) + 37y = 35.5
35-35y +37y = 35.5
0.5 = 2y
y = 0.25 = 37Cl
x = 1 - 0.25 = 0.75 = 35Cl
<u>Step 3: </u>
The ratio 35Cl/37Cl = 0.75/0.25 = 3/1
Answer: limiting reactant controls the amount of product formed in a chemical reaction.
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Answer:
The flask has to be closed during the hydrochloric acid and sodium carbonate reaction as the resultant gas got trapped inside the closed flask.
Explanation:
The hydrochloric acid and sodium carbonate reaction was exothermic that caused the pressure to decrease. The flask has to be closed during the hydrochloric acid and sodium carbonate reaction as the resultant gas got trapped inside the closed flask.
In exothermic reactions, energy is produced in the form of heat or light.
Here's how to do it:
<span>Balanced equation first: </span>
<span>Mg + HCl = H2 + MgCl2 unbalanced </span>
<span>Mg + 2 HCl = H2 = MgCl balanced </span>
<span>Therefore 1 mole Mg reacts with 2 moles Hcl. </span>
<span>50g Mg = ? moles (a bit over 2; you work it out) </span>
<span>75 g HCl = ? moles (also a bit over 2; you work it out) </span>
<span>BUT, you need twice the moles HCl; therefore it is the Mg that is in excess. (you can now work out how many moles are in excess, and therefore how much mg is left over). </span>
<span>So, 2 moles HCl produce 1 mole H2(g) </span>
<span>therefore, the amount of H2 produced is half the number of moles of HCl </span>
<span>At STP, there are X litres per mole of gas (look it up - about 22 from memory) </span>
<span>Therefore, knowing the moles of H2, you can calculate the volume</span>
