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2 years ago

• 3. You have a rock with a volume of 15cm3 and a mass of 45 g. What is its density? 3000 kg/m3

Chemistry

1 answer:

posledela2 years ago

6 0

Answer: d=2.165 g/cm3

Explanation:Due to the nature of it being cubed we can calculate such equation with the mass being 45 grams in which we get 2.165 grams per cenimeter cubed

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10.0 g Cu, C Cu = 0.385 J/g°C 10.0 g Al, C Al = 0.903 J/g°C 10.0 g ethanol, Methanol = 2.42 J/g°C 10.0 g H2O, CH2O = 4.18 J/g°C

Mazyrski [523]

Answer:

Lead shows the greatest temperature change upon absorbing 100.0 J of heat.

Explanation:

$Q=mc\Delte T$

Q = Energy gained or lost by the substance

m = mass of the substance

c = specific heat of the substance

ΔT = change in temperature

1) 10.0 g of copper

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the copper = c = 0.385 J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 0.385J/g^oC}=25.97^oC$

2) 10.0 g of aluminium

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the aluminium= c = 0.903 J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 0.903 J/g^oC}=11.07^oC$

3) 10.0 g of ethanol

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the ethanol= c = 2.42 J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 2.42 J/g^oC}=4.13 ^oC$

4) 10.0 g of water

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the water = c = 4.18J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 4.18 J/g^oC}=2.39 ^oC$

5) 10.0 g of lead

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the lead= c = 0.128 J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 0.128 J/g^oC}=78.125^oC$

Lead shows the greatest temperature change upon absorbing 100.0 J of heat.

3 0

3 years ago

The pressure in a car tire is 198 kPa at 27°C. After a long drive, the pressure

AlekseyPX

Answer : The temperature of the air in the tire is, 341 K

Explanation :

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

$P\propto T$

or,

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

where,

$P_1$ = initial pressure = 198 kPa

$P_2$ = final pressure = 225 kPa

$T_1$ = initial temperature = $27^oC=273+27=300K$

$T_2$ = final temperature = ?

Now put all the given values in the above equation, we get:

$\frac{198kPa}{300K}=\frac{225kPa}{T_2}$

$T_2=340.9K\approx 341K$

Therefore, the temperature of the air in the tire is, 341 K

5 0

3 years ago

What was the result of heating the mixture? All BUT ONE choice is correct.

snow_tiger [21]

Answer:

w gang alright

Explanation:

ay its b alright

4 0

3 years ago

Silicon dioxide (quartz) is usually quite unreactive but reacts readily with hydrogen fluoride according to the following equati

Scrat [10]

Here's your answer, hope this helps!

6 0

2 years ago

In a strong acid–strong base titration (both monoprotic), if 25.0 milliliters of the base is required to completely neutralize 2

taurus [48]

B)The concentration of the acid (C₁) is the same as that of the base (C₂).

V₁=V₂

n(acid)=C₁V₁
n(base)=C₂V₂

HX + YOH = YX + H₂O

n(acid)=n(base)

C₁V₁=C₂V₂

C₁=C₂

5 0

3 years ago

Read 2 more answers