Although internal energy<span> will not spontaneously flow from a cold region to a hot region, it can be forced to do so by doing work on the system.</span>Refrigerators<span> and </span>heat pumps<span> are examples of </span>heat engines<span> which cause energy to be transferred from a cold area to a hot area. Usually this is done with the aid of a </span>phase change<span>, i.e., a refrigerant liquid is forced to evaporate and extract energy from the cold area. Then it is compressed and forced to condense in the hot area, dumping its </span>heat of vaporization<span> into the hot area. ARE YOU FROM K12?</span>
Answer:
F = 5.83 10⁻¹⁷ N
Explanation:
The electric force is given by
F = k q₁ q₂ / r²
With Gauss's law electric field flow is equal to the charge inside the Gaussian surface, if we make a spherical surface around each drop, the force independent of small deformations due to air resistance
q₁ = q₂
F = 8.99 10⁹ (29 10⁻¹²)² / (0.36 10⁻²)²
F = 5.83 10⁻¹⁷ N
As the two drops have a charge of the same sign they repel
Answer:
It is found in the Atomic Nucleus
Explanation:
PLEASE MARK ME BRAINLIST PLEASE
Answer:
Assuming there is no heat loss to the surrounding.
Heat lost by iron equals heat gained by water.
0.2(450)(50-x)=0.2(4200)(x-30)
x=31.94 °C
Explanation:
Answer:
208 Joules
Explanation:
The radius of the circular path the charge moves, r = 26 m
The magnetic force acting on the charge particle, F = 16 N
Centripetal force, = m·v²/r
Kinetic energy, K.E. = (1/2)·m·v²
Where;
m = The mass of the charged particle
v = The velocity of the charged particle
r = The radius of the path of the charged particle
Whereby the magnetic force acting on the charge particle = The centripetal force, we have;
F = = m·v²/r = 16 N
(1/2) × r × = (1/2) × r × m·v²/r = (1/2)·m·v² = K.E.
∴ (1/2) × r × = (1/2) × 26 m × 16 N = = (1/2)·m·v² = K.E.
∴ 208 Joules = K.E.
The kinetic energy of an particle moving in the circular path, K.E. = 208 Joules.