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ZanzabumX [31]
3 years ago
7

How much force is needed to accelerate a 3 kg skateboard at 5 m/s2

Physics
2 answers:
TEA [102]3 years ago
4 0

Answer:15 newton force is required.

Explanation:

We know that

Force equal to mass x acceleration

3 kg x5 m/ s square

15( kg x m/s square)

15( newton)

15 N

Umnica [9.8K]3 years ago
3 0

The problem is fairly simple if you use the formula.

Formula: Force = (mass) x (acceleration)

3 x 5 = 15 newtons

Note: 3 kg is the mass of the skateboard, and 5 m/s2 is the acceleration.

Answer: 15 newtons

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4.1 A steel spur pinion has a pitch of 5 teeth/in, 20 full-depth teeth, and a 20° pressure angle. The pinion runs at a speed of
Vesnalui [34]

Answer:

15.07 ksi

Explanation:

Given that:

Pitch (P) = 5 teeth/in

Pressure angle (\Phi) = 20°

Pinion speed (n_p ) = 2000 rev/min

Power (H) = 30 hp

Teeth on gear (N_G) = 50

Teeth on pinion (N_p) = 20

Face width (F) = 1 in

Let us first determine the diameter (d) of the pinion.

Diameter (d) = \frac{N}{P}

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= 4 in

From the values of Lewis Form Factor Y for (n_p ) = 20 ; at 20°

Y = 0.321

To find the velocity (V); we use the formula:

V = \frac{\pi d n_p}{12}

V = \frac{\pi *4*2000}{12}

V = 2094.40 ft/min

For cut or milled profile; the velocity factor (K_v) can be determined as follows:

K_v = \frac{2000+V}{2000}

K_v = \frac{2000+2094.40}{2000}

= 2.0472

However, there is need to get the value of the tangential load(W^t), in order to achieve that, we have the following expression

W^t=\frac{T}{\frac{d}{2} }

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Finally, the bending stress is calculated via the formula:

\sigma = \frac{K_vW^tp}{FY}

\sigma = \frac{2.0472*472.69*5}{1*0.321}

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Answer:

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Heat capacity is given by the formula;

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Q = 202*450*80

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