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Rashid [163]
3 years ago
5

Rhythms that occur faster and slower than the beat are. Select one:. a. incorrect. b. not synchronized with the time signature.

c. called neumes. d. inevitable. e. not permitted
Physics
1 answer:
zlopas [31]3 years ago
4 0
Rhythms that occur faster and slower than the beat are b.<span>not synchronized with the time signature. The synchronization follows the same beat or rhythm. If the time signature say is lower than the original, then the rhythm should be faster. Otherwise, the rhythm is slower than the original one.</span>
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An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.275 T. If the kinetic energy of the electr
xxMikexx [17]

Answer:

Radius, r=2.14\times 10^{-5}\ m

Explanation:

It is given that,

Magnetic field, B = 0.275 T

Kinetic energy of the electron, E=4.9\times 10^{-19}\ J

Kinetic energy is given by :

E=\dfrac{1}{2}mv^2

v=\sqrt{\dfrac{2E}{m}}

v=\sqrt{\dfrac{2\times 4.9\times 10^{-19}}{9.1\times 10^{-31}}}            

v = 1037749.04 m/s

The centripetal force is balanced by the magnetic force as :

qvB\ sin90=\dfrac{mv^2}{r}

r=\dfrac{mv}{qB}

r=\dfrac{9.1\times 10^{-31}\times 1037749.04}{1.6\times 10^{-19}\times 0.275 }

r=2.14\times 10^{-5}\ m

So, the radius of the circular path is 2.14\times 10^{-5}\ m. Hence, this is the required solution.

3 0
3 years ago
Read 2 more answers
Which steps can be taken to translate the phrase “the height of a tree is increased by seven inches” into an algebraic expressio
ololo11 [35]

Answer:

Explanation:

height of tree = x

seven inches= 7

increaced by=+

3 0
2 years ago
Read 2 more answers
2. A solenoid. Suppose the south end of a bar magnet was introduced to the right end of this solenoid at a constant velocity. Wh
Studentka2010 [4]

Answer:

2) deflection must be towards the negative side of the voltage.

4) the correct statements are: b and c

Explanation:

2) This question is based on Faraday's law of induction, when we introduce a magnet in a solenoid an induced current is produced that generates a voltage that is given by

           E = - N d \phi_{B} / dt

where \phi_{B} = B. A

The bold are vectors

Therefore, when applying this formula to our case, the induction lines of the magnetic field increase as we approach the solenoid, as the South pole approaches the lines are in the direction of the magnet, therefore the normal to the solenoid that has an outgoing direction and the magnetic field has 180º between them and the cos 180 = -1; consequently the deflection must be towards the negative side of the voltage.

4) From the Faraday equation we can see that the inductive electromotive force depends

* The magnitude of B that changes over time

* The area of ​​the loop that changes over time

* The angle between B and the area that changes over time

* A combination of the above

With this analysis we will review the different alternatives given

a) False. It takes a temporary change and an absolute value of B

b) True. As the speed decreases, the change in B decreases, that is, dB / dt decreases

c) True. The current is induced in each turn, if there is a smaller number the total current will be smaller

d) False. A temporary change of area is needed, in addition to increasing the area the current increases

We can see that the correct statements are: b and c

5 0
3 years ago
Modern atomic theory states that atoms are neutral. how is this neutrality achieved in atoms? having more neutrons than protons
kolezko [41]
The answer is having fewer neutrons than protons or electrons.
8 0
3 years ago
Read 2 more answers
4) (5 points) Given are the magnitudes and orientations (with respect to x-axis) of 3
Kazeer [188]

Expand each vector into their component forms:

\vec A=(4.5\,\mathrm N)(\cos\theta_A\,\vec\imath+\sin\theta_A\,\vec\jmath)=(2.58\,\vec\imath+3.69\,\vec\jmath)\,\mathrm N

Similarly,

\vec B=(-1.23\,\vec\imath+0.860\,\vec\jmath)\,\mathrm N

\vec C=(-3.44\,\vec\imath-4.91\,\vec\jmath)\,\mathrm N

Then assuming the resultant vector \vec R is the sum of these three vectors, we have

\vec R=\vec A+\vec B+\vec C

\vec R=(-2.09\,\vec\imath-0.368\,\vec\jmath)\,\mathrm N

and so \vec R has magnitude

\|\vec R\|=\sqrt{(-2.09)^2+(-0.368)^2}\,\mathrm N\approx2.12\,\mathrm N

and direction \theta_R such that

\tan\theta_R=\dfrac{-0.368}{-2.09}\implies\theta_R=-170^\circ=190^\circ

5 0
3 years ago
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