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ryzh [129]
3 years ago
7

During a storm, a tree limb breaks off and comes to rest across a barbed wire fence at a point that is not in the middle between

two fence posts. The limb exerts a downward force of 176 N on the wire. The left section of the wire makes an angle of 12.5° relative to the horizontal and sustains a tension of 413 N. Find the (a) magnitude and (b) direction (as an angle relative to horizontal) of the tension that the right section of the wire sustains.

Physics
2 answers:
Aleks04 [339]3 years ago
5 0

Answer:

Magnitude - 11.83 Degree

Direction - 422.42 N

Explanation:

Given data:

Downward force on wire 176 N

Angle made by left section of wire 12.5 degree with horizontal

Tension force = 413 N

From figure

Applying quilibrium principle at point A

The vertical and horizontal force is 0

then we have

Tcos\theta = 413 N   ........1

176 = 413 sin 12.5 + Tsin\theta     .......2

Tsin\theta = 176 - 89.39  = 86.6.......3

divide equation 3 by 1

we get

\theta = tan^{-1} (0.2096)

theta = 11.83^o  ...........4

from equation 3 and 4

T = \frac{86.6}{sin 11.83}

T = 422.42 N

Whitepunk [10]3 years ago
4 0

Answer:

a. 12.12°

b. 412.04 N

Explanation:

Along vertical axis, the equation can be written as

T_1 sin14 + T_2sinA = mg

T_2sinA = mg - T_1sin12.5           ....................... (a)

Along horizontal axis, the equation can be written as

T_2×cosA = T_1×cos12.5    ......................... (b)

(a)/(b) given us

Tan A = (mg - T_1sin12.5) / T_1 cos12.5

 = (176 - 413sin12.5) / 413×cos12.5

A = 12.12 °

(b) T2 cosA = T1 cos12.5

T2 = 413cos12.5/cos12.12

= 412.04 N

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15. A locomotive moved 18.0 m [W] in a time of 6.00 s and stopped. After stopping, the
mariarad [96]

Answer:

Distance = 30m

Displacement = 6m W

Explanation:

Given the following:

Movement 1 = 18m W

Movement 2 = 12m E

Diatance is a scalar quantity with only magnitude and no direction. That is, in Calculating the distance moved by the locomotive, the direction of travel or movement of the object is not considered. It only measures the total amount of movement made during the Time of motion.

Therefore, total distance traveled equals :

Movement 1 + movement 2

18m + 12m = 30m

B) Displacement also measures the movement made by an object. However, Displacement is a vector quantity and therefore, considers both magnitude and direction of travel of the object. Therefore, it measures the overall change in position of the object from its starting position.

Therefore, Displacement of the locomotive equals:

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Examples of fixed pulley?​
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One example of a fixed pulley is a Flag Pole

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Three people pull simultaneously on a stubborn donkey. Jack pulls eastward with a force of 64.7 N, Jill pulls with 61.5 N in the
USPshnik [31]

Answer:

 F = 241.8 N    θ = -18.7

Explanation:

To find the net force, we use Newton's second law, for this we decompose the force using trigonomer

Force 2

    F2 = 61.5 N

   cos 45 = F₂ₓ / F2         F₂ₓ = F2 cos 45

   sin 45 = F₂_y / F2          F₂_y = F2 sin 45

     

force 3

     F3 = 171 N

     cos 45 = F₃ₓ / F3

     sin 45 = F₃_y / F3

the total force can be found with its components

axis x direction (East-West)

      Fₓ = 64.7 +61.5 cos 45 + 171 cos 45

      Fₓ = 229.1 N

Y axis (direction North -Sur)

     F_y = 61.5 sin 45 - 171 sin 45

     F_y = - 77,428 N

the resulting force is

      F = Fx i ^ + Fy j ^

      F = (229.1 i⁻ 77,428 j⁾ N

we can use the Pythagorean theorem to find the module

       F = √ (229.1 2 + 77,428 2)

       F = 241.8 N

let's use trigonometry to find the direction

     tan θ = F_y / Fₓ

     θ = tan⁻¹ (F_y / Fₓ)

     θ = tan⁻¹ (-77,428 / 229.1)

     θ = -18.7

4 0
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