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nikklg [1K]
3 years ago
8

Please help!!! Simplify in standard form. (2x5+x3−3x4−x+8)−(7x5+2x4−12+6x−5x3+x2)

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
7 0
<span>(2x^5+x^3−3x^4−x+8)−(7x^5+2x^4−12+6x−5x^3+x^2)
= </span>2x^5 − 3x^4 + x^3  −x + 8 − 7x^5  - 2x^4 + 5x^3 − x^2 − 6x + 12
= − 5x^5 − 5x^4 + 6x^3 − x^2 − 7x + 20

hope it helps
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My choice would be to solve for x using the first equation.

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On second thought, it might actually be easier to solve either equation for 8y. That term then directly substitutes into the other equation (equivalent to adding the two equations).
.. 8y = 3x -11 . . . . . from the second equation
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3 years ago
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3 years ago
Consider quadrilateral ABCD shown.
podryga [215]

Answer:

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5 0
3 years ago
Read 2 more answers
4 - x + <img src="https://tex.z-dn.net/?f=6%5E%7B2%7D" id="TexFormula1" title="6^{2}" alt="6^{2}" align="absmiddle" class="latex
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Answer:

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Step-by-step explanation:

The instructions here are probably "solve for x."  Please include them.

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Now combine like terms.  4 and 36 combine to 40:  40 - x ≥ 21, and so:

19 - x ≥ 0

Adding x to both sies results in

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3 0
3 years ago
Someone please help me on this math problem!
Galina-37 [17]

Look at the picture.

Therefore we have the equation:

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3y = 48      <em>divide both sides by 3</em>

y = 16



3x + 7 = 5x - 21            <em>subtract 7 from both sides</em>

3x = 5x = -28         <em>subtract 5x from both sides</em>

-2x = -28     <em>divide both sides by (-2)</em>

x = 14

3 0
3 years ago
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