In fact, the force Rahul exerts on Earth corresponds to the force of gravity. But Rahul's weight is, in fact, the force of gravity exerted by the Earth on Rahul, and these two forces correspond to the action-reaction pair of Newton's third law, which states that the two forces are equal.
12 MPH
I DIDNT do the math my brother did hes in colledge so good lucks guys
Answer: 0.798 m
Explanation:
Given
Mass of the spring oscillator, m = 1.48 kg
Force constant of the spring, k = 35.4 N/m
Speed of oscillation, v = 3.9 m/s
Kinetic Energy = 1/2 mv²
Kinetic Energy = 1/2 * 1.48 * 3.9²
KE = 0.5 * 22.5108
KE = 11.26 J
Using the law of conservation of Energy. The Potential Energy of the system is equal to Kinetic Energy of the system
KE = PE
PE = 1/2kx²
11.26 = 1/2 * 35.4 * x²
11.26 = 17.7x²
x² = 11.26 / 17.7
x² = 0.6362
x = √0.6362
x = 0.798 m
From the calculation, the speed of sound at 10 K is 63.5 m/s.
<h3>What is the speed of sound?</h3>
We know that the speed of sound is directly proportional to the temperature of the body thus we can write;
V1/V2 = √T1/T2
Then;
T1 = 0 degrees or 273 K
T2 = 10 K
V1 = 330 m/s
V2 = ?
330/T2 = √273/10
330/T2 = 5.2
330 = 5.2T2
V2 = 330/5.2
V2 = 63.5 m/s
Learn more about speed of sound:brainly.com/question/15381147
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I will assume that big Joe is big Jim. The equation for the momentum is p=m*v, where m is the mass of the body and v is the velocity. Big Joe has a mass m=105 kg and speed v=5.2 m/s. When we input the numbers:
p=105*5.2=546 kg*(m/s).
So big Joe's momentum before the collision is p=546 kg*(m/s).
